C = 1.6b
c + b = 442
1.6b + b = 442
2.6b = 442
b = 442 / 2.6
b = 170 <== Boston
c = 1.6b
c = 1.6(170)
c = 272 <== Colorado Springs
The value of f(-3) is 5.
In order to find this answer, we are going to input -3 in for x (this is what the notation f(-3) means).
f(x)=| x-2 |
f(-3)=| -3 -2 |
f(-3)=| -5 |
Now we have to take the absolute value.
f(-3) = 5
Answer:
C?
Step-by-step explanation:
A) Jared makes x of a goodie bag per hour. How many
can he make in y of an hour?
B) Jared makes x of a goodie bag per hour. How many
can he make in y of an hour?
C) Jared has x of an hour left to finish making goodie bags. It takes him y of an hour to make each goodie bag. How many goodie bags can he make?
D) id k
Quotient is the answer to a division problem, so we need to find a problem that needs to divide x and y to find the answer. It isn't A or B, since they are asking for y, not the quotient. I have no idea what D is. C makes sense, so C might be the answer.
It tells us how much time he has(x), and how long it takes him to make 1 bag(y), and we need to find the answer, which is the quotient.
So C is the answer.
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hope it helps
Answer:
First answer choice
Step-by-step explanation:
Cards are drawn, one at a time, from a standard deck; each card is replaced before the next one is drawn. Let X be the number of draws necessary to get an ace. Find E(X) is given in the following way
Step-by-step explanation:
- From a standard deck of cards, one card is drawn. What is the probability that the card is black and a
jack? P(Black and Jack) P(Black) = 26/52 or ½ , P(Jack) is 4/52 or 1/13 so P(Black and Jack) = ½ * 1/13 = 1/26
- A standard deck of cards is shuffled and one card is drawn. Find the probability that the card is a queen
or an ace.
P(Q or A) = P(Q) = 4/52 or 1/13 + P(A) = 4/52 or 1/13 = 1/13 + 1/13 = 2/13
- WITHOUT REPLACEMENT: If you draw two cards from the deck without replacement, what is the probability that they will both be aces?
P(AA) = (4/52)(3/51) = 1/221.
- WITHOUT REPLACEMENT: What is the probability that the second card will be an ace if the first card is a king?
P(A|K) = 4/51 since there are four aces in the deck but only 51 cards left after the king has been removed.
- WITH REPLACEMENT: Find the probability of drawing three queens in a row, with replacement. We pick a card, write down what it is, then put it back in the deck and draw again. To find the P(QQQ), we find the
probability of drawing the first queen which is 4/52.
- The probability of drawing the second queen is also 4/52 and the third is 4/52.
- We multiply these three individual probabilities together to get P(QQQ) =
- P(Q)P(Q)P(Q) = (4/52)(4/52)(4/52) = .00004 which is very small but not impossible.
- Probability of getting a royal flush = P(10 and Jack and Queen and King and Ace of the same suit)
