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3 years ago

Aspen has 10 pairs of white socks and 1 pair of red socks. What is the chance that Aspen wears a pair of black socks?

Mathematics

2 answers:

STatiana [176]3 years ago

7 0

Answer:

no chance

Step-by-step explanation:

he doesn't have any black socks

Jobisdone [24]3 years ago

3 0

Answer:

Step-by-step explanation:

Of the ten socks,

10/11 chance of wearing white socks

1/11 chance of wearing red socks

0/11 chance of wearing any OTHER color

Black socks fall into the final row, which is the OTHER color, meaning there is no chance he can wear black socks.

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Simplify:<br> 4-5-9<br> PLEASE HURRY!!! THANK U

Masja [62]

Answer:

The answer is -10.

Step-by-step explanation:

4 - 5 - 9

-1 - 9

-10

6 0

3 years ago

Read 2 more answers

Use mathematical induction to prove the statement is true for all positive integers n, or show why it is false:

kondaur [170]

$\text{Proof by induction:}$
$\text{Test that the statement holds or n = 1}$

$LHS = (3 - 2)^{2} = 1$
$RHS = \frac{6 - 4}{2} = \frac{2}{2} = 1 = LHS$
$\text{Thus, the statement holds for the base case.}$

$\text{Assume the statement holds for some arbitrary term, n= k}$
$1^{2} + 4^{2} + 7^{2} + ... + (3k - 2)^{2} = \frac{k(6k^{2} - 3k - 1)}{2}$

$\text{Prove it is true for n = k + 1}$
$RTP: 1^{2} + 4^{2} + 7^{2} + ... + [3(k + 1) - 2]^{2} = \frac{(k + 1)[6(k + 1)^{2} - 3(k + 1) - 1]}{2} = \frac{(k + 1)[6k^{2} + 9k + 2]}{2}$

$LHS = \underbrace{1^{2} + 4^{2} + 7^{2} + ... + (3k - 2)^{2}}_{\frac{k(6k^{2} - 3k - 1)}{2}} + [3(k + 1) - 2]^{2}$
$= \frac{k(6k^{2} - 3k - 1)}{2} + [3(k + 1) - 2]^{2}$
$= \frac{k(6k^{2} - 3k - 1) + 2[3(k + 1) - 2]^{2}}{2}$
$= \frac{k(6k^{2} - 3k - 1) + 2(3k + 1)^{2}}{2}$
$= \frac{k(6k^{2} - 3k - 1) + 18k^{2} + 12k + 2}{2}$
$= \frac{k(6k^{2} - 3k - 1 + 18k + 12) + 2}{2}$
$= \frac{k(6k^{2} + 15k + 11) + 2}{}$
$= \frac{(k + 1)[6k^{2} + 9k + 2]}{2}$
$= \frac{(k + 1)[6(k + 1)^{2} - 3(k + 1) - 1]}{2}$
$= RHS$

Since it is true for n = 1, n = k, and n = k + 1, by the principles of mathematical induction, it is true for all positive values of n.

3 0

3 years ago

A triangle has vertices at B(-3,0), C(2, -1), D(-1,2). Which series of transformations would produce an image with vertices B"(4

Alik [6]

Answer:

(b) (x, y) ⇒ (-x, y); (x, y) ⇒ (x + 1, y + 1)

Step-by-step explanation:

A graph shows the image is consistent with reflection over the y-axis

(x, y) ⇒ (-x, y)

and translation right 1, up 1

(x, y) ⇒ (x +1, y +1)

These transformations are listed in the second choice.

In the attachment, the original image is blue, the reflected image is purple, and the final translated image is red.

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lilavasa [31]

Answer: 126

Step-by-step explanation:

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tester [92]

Answer:

Step-by-step explanation:

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