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4 years ago

Evaluate -8(x - 3y) when x = -2 and y= -4

Mathematics

1 answer:

liraira [26]4 years ago

6 0

-8(-2-3[-4])
-8(-2+12)
16+12
28

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Leno4ka [110]

Answer:

$\frac{s^2-25}{(s^2+25)^2}$

Step-by-step explanation:

Let's use the definition of the Laplace transform and the identity given: $\mathcal{L}[t \cos 5t]=(-1)F'(s)$ with $F(s)=\mathcal{L}[\cos 5t]$ .

Now, $F(s)=\int_0 ^{+ \infty}e^{-st}\cos(5t) dt$ . Using integration by parts with u=e^(-st) and dv=cos(5t), we obtain that $F(s)=\frac{1}{5}\sin(5t)e^{-st} |_{0}^{+\infty}+\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt=\int_0 ^{+ \infty}e^{-st}\sin(5t) dt$ .

Using integration by parts again with u=e^(-st) and dv=sin(5t), we obtain that

$F(s)=\frac{s}{5}(\frac{-1}{5}\cos(5t)e^{-st} |_{0}^{+\infty}-\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}(\frac{1}{5}-\frac{s}{5}\int_0^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}-\frac{s^2}{25}F(s)$ .

Solving for F(s) on the last equation, $F(s)=\frac{s}{s^2+25}$ , then the Laplace transform we were searching is $-F'(s)=\frac{s^2-25}{(s^2+25)^2}$

3 0

3 years ago

What are the first and last deciles of the standard Normal distribution?

aliya0001 [1]

My best Guess is

1.282 for upper . , -1.282 for lower.

Hope this Helps

-Dante

5 0

3 years ago

Simplify 4xy + 9x - 3y + z + xy

Contact [7]

4xy + 9x - 3y + z + xy

Combine Like Terms
=4xy+9x+−3y+z+xy
=(4xy+xy)+(9x)+(−3y)+(z)
=5xy+9x+−3y+z

Answer =5xy+9x−3y+z

I hope this helps, can I get brainliest thanks

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3 years ago

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Brandon has a garden in his backyard he picked 66 from six tomato plants what is the ratio of tomato plants two tomatoes picked

Tom [10]

11 Picked Off 6 Plants.

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3 years ago

Plz Help me with this its due today!!!!PLZzzz

Sedaia [141]

The second choice
7+ -13= -6

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3 years ago

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