Answer:
How far did the ship travel between the two observations of the lighthouse = 9.29
Step-by-step explanation:
the first step to answer this question is drawing the illustration as the attachment.
P is the ship, R is the light house and Q is the bearing.
PR is the distance between the ship and the light house, PR = 10.5
∠P = 42.8°, ∠Q = 59.7°
Thus, ∠R = 180° - ∠P - ∠Q
= 180° - 42.8°- 59.7°
= 77.5°
PQ is the the distance of the ship moving. We can use the sinus equation
= ![\frac{PQ}{sin Q}](https://tex.z-dn.net/?f=%5Cfrac%7BPQ%7D%7Bsin%20Q%7D)
= ![\frac{PQ}{sin 59.7°}](https://tex.z-dn.net/?f=%5Cfrac%7BPQ%7D%7Bsin%2059.7%C2%B0%7D)
PQ = (
)(sin 59.7°)
= 9.29
9 + 5 + 4 + 7 = 25
Ratio = 5 : 25
Ratio = 1 : 5 <==== answer
The effective annual interest rate is:
i = (1 + 0.064/12)^12 - 1 = 0.066
In year 1: the interest is $613.80 (multiple $9300 by 0.066)
In year 2: the interest is $654.31 (add interest from year 1 to $9300 and multiply by 0.066)
In year 3: the interest is $656.98 (do the same as year 2)
In year 4: the interest is $657.16
The total interest is: $2582.25
The present worth of this amount is:
P = 2582.23 / (1 + 0.066)^4 = $1999.72
The answer is $1999.72.
Answer:
y = -3x + 21
Step-by-step explanation:
(5,6)
y = mx + b
6 = -3 × 5 + b
solving for b
b = 6 - (-3)(5)
b = 21
Therefore,
y = -3x + 21