IN Δ MLN:
∠M = 18.3 , ∠L = 98.6 AND ∠N = 180 - (∠M + ∠L) = 180 - (18.3 + 98.6 ) = 63.1
IN Δ FGH:
∠F = 98.6 , ∠G = 61.1 AND ∠H = 180 - (∠F + ∠G ) = 180 - (98.6 + 61.1 ) = 20.3
∴ ONLY ∠N = ∠F = 98.6
There is no other <span>congruent </span>angles
So, The correct statement is :
Inaccurate. The triangles are not similar because angle M is not congruent to angle H, and angle N is not congruent to angle G.
12x^2y^2+2xy-2 with problems like these use the app “Photomath” it will help you a lot.
Answer:
-6s-c+1
Step-by-step explanation:
(-3s-4c+1)+(-3s+3c)
We have been given the above expression. To find the sum, we simply collect the like terms and combine them;
(-3s-4c+1)+(-3s+3c) = -3s + -3s -4c + 3c + 1
-3s + -3s -4c + 3c + 1 = -3s - 3s + 3c - 4c + 1
-3s - 3s + 3c - 4c + 1 = -6s - c + 1
Therefore;
(-3s-4c+1)+(-3s+3c) = -6s-c+1
Answer:
Step-by-step explanation:
Fractions
Answer:
300 miles
Step-by-step explanation:
The distance equation is D = RT
Where
D is the distance
R is the rate
T is the time
<u>Mindy</u>
8 am to 1 pm = 5 hours
<u>Kelly</u>
8 am to 2 pm = 6 hours
Kelly's rate is 10 mph SLOWER than mindy, so if we let Mindy's rate be "m", so Kelly's rate will be " m - 10 "
Now using the distance equation, we can write:
Mindy >>> D = RT >>> D = 5m
Kelly >>> D = RT >>> D = 6(m-10) >>> D = 6m - 60
Since both the distances are equal, we can write:
5m = 6m - 60
m = 60
We want the distance, we know:
D = 5m
D = 5(60)
D = 300 miles
The distance is 300 miles
