Answer:
Step-by-step explanation:
You know that ...
- cos(θ)² = 1 - sin(θ)²
- tan(θ) = sin(θ)/cos(θ)
- cosine is negative in the third quadrant (where π < θ < 3π/2)
Using what you know about the relationships of these trig functions, you can find ...
cos(θ)² = 1 - ((-√3)/2)² = 1 - 3/4 = 1/4
cos(θ) = -1/2 . . . . . negative square root of 1/4
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tan(θ) = sin(θ)/cos(θ) = ((-√3)/2)/(-1/2)
tan(θ) = √3
I beleive it is 6(2) + 3 (1) + 1(5) = 20 points :)
(3)(-5x+y=-3)
(5)(3x-8y=24)
-15x+3y=-9
15x-40y=120
3y=-9
-40y=120
-37y=111
Divide both sides by -37
y=-3
To solve for x. Choose one equation from the given and plug what you get in Y.
I'll choose, -5x+y=-3
So, -5x+(-3)=-3
-5x=0
Divide both sides by -5
x=0/-5
Hope, this helps.