Question

A mass attached to the end of a spring is oscillating with a period of 2.25 s on a horizontal frictionless surface. The mass was released from rest at
t = 0
from the position
x = 0.0480 m.
Determine the location of the mass at
t = 5.85 s?

Answer 1

Answer:

$X=0.0389m$

Explanation:

From the question we are told that:

Period of spring $T_s=2.25s$

Initial Position of Mass $x=0.0480m$

Final Mass period $T_f=5.85s$

Generally the equation for the Mass location is mathematically given by

$X=xcos*\frac{2\pi T_s}{T_f}$

$X=0.048*cos*\frac{2\pi 5.85}{2.25}$

$X=0.0389m$