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swat32
1 year ago
10

draw the process and control scheme for this system if a constraint controller is used, such that when the smaller of two parall

el control valves reached 100%, then the controller output is routed
Physics
1 answer:
never [62]1 year ago
8 0

Method controllers hold the output of manner variables inclusive of temperature, stress, float, or degree inside a pre-set range.

Manner controllers keep the output of gadget variables at the side of temperature, pressure, drift, or diploma internal a pre-set range. They use comments from sensors to pick out any deviation from a setpoint and robotically modify output until.

Parameters are lower back within range.

The task of a constraint manipulate scheme is to push a goal variable as far as possible in the preferred course. With distinct phrases, The intention variable shall attain is relying at the purpose maximum or minimum price with out violating some different obstacles.

Constraints are used to restriction the kind of facts that could go proper right into a table. This guarantees the accuracy and reliability of the records within the table. If there can be any violation among the constraint and the information movement, the movement is aborted. Constraints may be column stage or table stage.

Learn more about constraint controller here:- brainly.com/question/15102549

#SPJ4

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Modern observations have shown that the geometry of the universe is ____.
lesantik [10]

Modern observations have shown that the geometry of the universe is flat and the universe mist be infinite.

<h3>What is geometry?</h3>

Geometry refer to a branch of mathematics that encapsulates measurements of lines, shapes, dimensions, points and shapes.

Therefore, Modern observations have shown that the geometry of the universe is flat and the universe mist be infinite.

Learn more about geometry below.

brainly.com/question/19241268

#SPJ11

8 0
1 year ago
A block is at rest on a plank whose angle can be varied. The angle is gradually increased from 0 deg. At 31.8°, the block starts
galina1969 [7]

Answer:

\mu_s = 0.62

\mu_k = 0.415

The motion of the block is downwards with acceleration 1.7 m/s^2.

Explanation:

First, we will calculate the acceleration using the kinematics equations. We will denote the direction along the incline as x-direction.

x - x_0 = v_0t + \frac{1}{2}at^2\\3.4 = 0 + \frac{1}{2}a(2)^2\\a = 1.7~m/s^2

Newton’s Second Law can be used to find the net force applied on the block in the -x-direction.

F = ma\\F = 1.7m

Now, let’s investigate the free-body diagram of the block.

Along the x-direction, there are two forces: The x-component of the block’s weight and the kinetic friction force. Therefore,

F = mg\sin(\theta) - \mu_k mg\cos(\theta)\\1.7m = mg\sin(31.8) - \mu_k mg\cos(31.8)\\1.7 = (9.8)\sin(\theta) - mu_k(9.8)\cos(\theta)\\mu_k = 0.415

As for the static friction, we will consider the angle 31.8, but just before the block starts the move.

mg\sin(31.8) = \mu_s mg\cos(31.8)\\\mu_s = tan(31.8) = 0.62

5 0
3 years ago
Sally goes on a hike. The distance she walks compared to the amount of time she walks is shown on the graph. Which statement is
Neko [114]
According to the task there should be the graph that supports Sally's hike, but after looking on the options it seems that Sally doesn't walks at a constant rate and there is the negative option that coincides with my thoughts. So, I bet the false statement is the third option represented in the scale above.
5 0
3 years ago
A research vessel is mapping the bottom of the ocean using sonar. It emits a short sound pulse called "ping" downward. The frequ
Elena L [17]

Answer:

The ocean is 6485.6m deep when measured from the vessel

Explanation:

v=1474m/s

t=8.88s

let d represent distance from the vessel to the ocean bottom.

an echo travels a distance equivalent to 2d, that is to and fro after it reflects from the obstacle.

velocity=\frac{distance}{time}\\ v=\frac{2d}{t} \\vt=2d\\d=\frac{vt}{2}

d=\frac{1474*8.8}{2}

d= 6485.6m

7 0
2 years ago
A block of a plastic material floats in water with 42.9% of its volume under water. What is the density of the block in kg/m3?
adell [148]

To solve this problem we will apply the principle of buoyancy of Archimedes and the relationship given between density, mass and volume.

By balancing forces, the force of the weight must be counteracted by the buoyancy force, therefore

\sum F = 0

F_b -W = 0

F_b = W

F_b = mg

Here,

m = mass

g =Gravitational energy

The buoyancy force corresponds to that exerted by water, while the mass given there is that of the object, therefore

\rho_w V_{displaced} g = mg

Remember the expression for which you can determine the relationship between mass, volume and density, in which

\rho = \frac{m}{V} \rightarrow m = V\rho

In this case the density would be that of the object, replacing

\rho_w V_{displaced} g = V\rho g

Since the displaced volume of water is 0.429 we will have to

\rho_w (0.429V) = V \rho

0.429\rho_w= \rho

The density of water under normal conditions is 1000kg / m ^ 3, so

0.429(1000) = \rho

\rho = 429kg/m^3

The density of the object is 429kg / m ^ 3

7 0
2 years ago
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