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evablogger [386]
2 years ago
11

Ishani and John now try a problem involving a charging capacitor. An uncharged capacitor with C = 6.81 μF and a resistor with R

= 5.8 105 Ω are connected in series to a 12.0 V battery. The switch is closed at time t = 0, allowing the capacitor to charge. Find the maximum charge on the capacitor and the maximum current through the resistor.
Physics
1 answer:
DENIUS [597]2 years ago
5 0

Answer:

Q=81.72\times10^{-6}C

I=2.1\times10^{-5}A

Explanation:

The maximum charge on the capacitor will be, at the end of the process, given by the formula (and for our values):

Q=CV=(6.81\times10^{-6}F)(12V)=81.72\times10^{-6}C

The maximum current on the resistor will be, at the beginning of the process, given by the formula (and for our values):

I=\frac{V}{R}=\frac{12V}{5.8\times10^{5}\Omega}=2.1\times10^{-5}A

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