Question

Ishani and John now try a problem involving a charging capacitor. An uncharged capacitor with C = 6.81 μF and a resistor with R = 5.8 105 Ω are connected in series to a 12.0 V battery. The switch is closed at time t = 0, allowing the capacitor to charge. Find the maximum charge on the capacitor and the maximum current through the resistor.

Answer 1

Answer:

$Q=81.72\times10^{-6}C$

$I=2.1\times10^{-5}A$

Explanation:

The maximum charge on the capacitor will be, at the end of the process, given by the formula (and for our values):

$Q=CV=(6.81\times10^{-6}F)(12V)=81.72\times10^{-6}C$

The maximum current on the resistor will be, at the beginning of the process, given by the formula (and for our values):

$I=\frac{V}{R}=\frac{12V}{5.8\times10^{5}\Omega}=2.1\times10^{-5}A$