Answer:
The dimension of this rectangle = 2mm by 21mm
Where 2 mm = Width of the rectangle
21 mm = Length of the rectangle.
Step-by-step explanation:
The formula for the perimeter of a rectangle = 2(L + W)
= 2L + 2W
The perimeter = 46 mm
L = 3x + 3
W = x - 4
P = 2L + 2W
46mm = 2(3x + 3) + 2(x - 4)
46 = 6x + 6 + 2x - 8
Collect like terms
46 +8 -6 = 6x + 2x
48 = 8x
x = 48/8
x = 6
Since the Length = 3x + 3
= 3(6) + 3
= 18 + 3
= 21mm
Since the Width = x - 4
= 6 - 4
= 2mm
Therefore, the dimension of this rectangle = 2mm by 21mm
Where 2 mm = Width of the rectangle
21 mm = Length of the rectangle.
<span>7N - 2N + 3P + 2P
Combine like terms:
7N-2N=5N
3P+2P=5P
Put them together to get :
5N+5P
Final answer:
A</span>
The calendar obviously has an integral number of years and months in 400 years. If it has an integral number of weeks, then it will repeat itself after that time. The rules of the calendar eliminate a leap year in 3 out of the four century years, so there are 97 leap years in 400 years. The number of excess days of the week in 400 years can be found by ...
(303·365) mod 7 + (97·366) mod 7 = (2·1 + 6·2) mod 7 = 14 mod 7 = 0
Thus, there are also an integral number of weeks in 400 years.
The first day of the week is the same at the start of every 400-year interval, so the calendar repeats every 400 years.
Answer:(3x+7)(x+2)
Step-by-step explanation:
