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Luden [163]
3 years ago
13

Substance D - It has a high melting and boiling point. The arrangement of its particles are closely packed. It cannot conduct el

ectricity unless molten or dissolved in water. What type of element is substance D?
Chemistry
1 answer:
S_A_V [24]3 years ago
6 0

Answer:

ionic

Explanation:

because when in molten or dissolved in water  ions are free to move and carry  a charge however when in solid the ions are fixed in position so can't carry a charge.

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What animals are in the Arctic Tundra?
ehidna [41]

Answer:

Polar Bears

Arctic Foxes

Seals

Penguins

They all live in the cold, so they all must live in the Arctic Tundra ;)

6 0
3 years ago
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When may a hypothesis be revised?
Mashutka [201]
When it has been disproven
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3 years ago
Using the following general equation for a nuclear reaction, complete the statements below.
sammy [17]
Atomic number is written in subscript:
Uranium atomic number =92

Mass of neutron is the superscript value times the quantity (moles):
3*1= 3

Atomic mass is approximately equivalent to the number of protons and neutrons in the atom (the mass number). It's written in superscript:

Kr=92

No. of neutrons = Mass number (in superscript) - Atomic number ( in subscript)

= 141-56= 85

No. of neutrons in reactants are: 3
8 0
4 years ago
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What season is it in earths northern hemisphere when earths northern hemisphere tilts toward the sun
valina [46]

Answer:

Summer

Explanation:

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8 0
3 years ago
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If 60 ml of naoh solution neutralizes 40 ml of 0.50 m h2so4, the concentration of the naoh solution is most nearly:
Bad White [126]
<span>The balanced chemical equation for this reaction is:

2NaOH (aq)+H2SO4 (aq) → Na2SO4 (aq)+2H2O (l)

According to question, 60 ml of NaOH solution was used for neutralizing 40 ml of 0.50M H2SO4.

The no. of moles of H2SO4 is calculated using the equation:
mol solute = (molarity) (L soln)

mol H2SO4 = 0.50 M x 0.040 L = 0.02 moles of H2SO4

As per the equation, the number of moles of NaOH used is:

0.02 moles of H2SO4 (2 mol NaOH) (1 mol H2SO4) = 0.04 moles of NaOH

Therefore, using the given volume of NaOH, the concentration or molarity of NaOH can be calculated using the formula :

Molarity = mol solute/L soln = 0.04 mol NaOH/0.06 L = 0.67 M

Therefore, the concentration of NaOH is 0.67 M.</span>
3 0
4 years ago
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