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4 years ago

Using the following general equation for a nuclear reaction, complete the statements below.

Chemistry

2 answers:

sammy [17]4 years ago

8 0

Atomic number is written in subscript:
Uranium atomic number =92

Mass of neutron is the superscript value times the quantity (moles):
3*1= 3

Atomic mass is approximately equivalent to the number of protons and neutrons in the atom (the mass number). It's written in superscript:

Kr=92

No. of neutrons = Mass number (in superscript) - Atomic number ( in subscript)

= 141-56= 85

No. of neutrons in reactants are: 3

MatroZZZ [7]4 years ago

3 0

Answer:

the answers are

Explanation:

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How many atoms are there in one molecule of C22H44O?

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Answer:

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4 years ago

How many moles of cacl2 are in 250 ml of a 3.0 m of cacl2 solution?

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A bubble of helium gas has a volume of 0.650 cm3 near the bottom of a large aquarium where the pressure is 1.54 atm and the temp

aleksandrvk [35]

Answer:

1.005 cm³

Explanation:

Using Ideal gas equation for same mole of gas as

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}$

Given ,

V₁ = 0.650 cm³

V₂ = ?

P₁ = 1.54 atm

P₂ = 1.01 atm

T₁ = 12°C

T₂ = 16 ºC

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (12 + 273.15) K = 285.15 K

T₂ = (16 + 273.15) K = 289.15 K

Using above equation as:

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}$

$\frac {{1.54}\times {0.650}}{285.15}=\frac {{1.01}\times {V_2}}{289.15}$

Solving for V₂ , we get:

V₂ = 1.005 cm³

3 0

3 years ago

Based on the activity series provided, which reactants will form products? F > Cl > Br > I CuI2 Br2 Right arrow. Cl2 Al

AleksAgata [21]

The reactants based on the reactivity capable of forming the products are $\rm CuI_2\;and\;Br_2$ . Thus, option A is correct.

The reactivity series has been the arrangement of the elements based on their reactivity. The highly reactive element has been capable of replacing the less reactive element in the compound, and form the product.

In the following reactions, the new product has been formed by:

$\rm CuI_2\;and\;Br_2$

From the reactivity series, Br has been more reactive than I, and thereby replaces iodine in the compound for the formation of product.

$\rm Cl_2\;and\;AlF_3$

The compound has been formed with F. Cl has been less reactive than F, and will not be able to form the product.

$\rm Br_2\;and\;NaCl$

The compound has been formed with Cl. Br has been less reactive than Cl, thus will not displaces Cl for the formation of new product.

$\rm CuF_2\;and\;I_2$

The compound has been formed with F. I has been less reactive than F, and will not be able to form the product.

The reactants that will be able to form the products have been $\rm CuI_2\;and\;Br_2$ . Thus, option A is correct.

For more information about the reactivity series, refer to the link:

brainly.com/question/10443908

5 0

3 years ago