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aleksandrvk [35]
3 years ago
15

PLS ANSWER FAST WILL MARK BRAINLIEST

Physics
1 answer:
densk [106]3 years ago
7 0

In position A

<em>The</em><em> </em><em>mirror </em><em>has</em><em> </em><em>to</em><em> </em><em>be</em><em> </em><em>observed</em><em> </em><em>in</em><em> </em><em>the</em><em> </em><em>ray</em><em> </em><em>reflected</em><em> </em><em>from</em><em> </em><em>the</em><em> </em><em>mi</em><em>rror</em><em>.</em>

<em>Since</em><em> </em><em>the</em><em> </em><em>the</em><em> </em><em>angle</em><em> </em><em>of</em><em> </em><em>reflec</em><em>tion</em><em> </em><em>is</em><em> </em><em>equal</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>angle</em><em> </em><em>of</em><em> </em><em>incidence</em><em>,</em><em> </em><em>the</em><em> </em><em>reflected</em><em> </em><em>ray</em><em> </em><em>must</em><em> </em><em>be</em><em> </em><em>in</em><em> </em><em>equal</em><em> </em><em>path</em><em> </em><em>as</em><em> </em><em>the</em><em> </em><em>incident</em><em> </em><em>ray</em><em>.</em>

<em>That</em><em> </em><em>phenomenon</em><em> </em><em>is</em><em> </em><em>only</em><em> </em><em>in</em><em> </em><em>diagram</em><em> </em><em>A</em>

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What is the mass of an object going 25 m/s and has a momentum of 140<br> kg m/s?
slega [8]

Answer:

The answer would be 5.6 kg of a mass.

Explanation:

p= mv

m= p/ v

The explanation of that is:

momentum = mass× velocity

mass= momentum / velocity

Hope this helped!

7 0
3 years ago
An 80 kg person jumps out of a plane. If the air resistance is 800 N, find the<br><br> Acceleration.
sertanlavr [38]

Answer:

The acceleration is 10 m/s²

Explanation:

The question seeks to show the relationship between force, mass and acceleration. Hence, the formula to be used here is that of force which is shown below

F = ma

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m is the mass (80 kg)

a is the acceleration (unknown)

From the formula above (Force = mass multiplied by acceleration)

800 N = 80 kg × a

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a = 10 m/s²

4 0
3 years ago
Read 2 more answers
Help me please Ima give brainiest
julsineya [31]
Sand. You can identify tiny sugar crystals.


4 0
3 years ago
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(i) (a) what is the force per meter of length on a straight wire carrying a 9.75 a current when perpendicular to a 0.81 t unifor
Andrew [12]
The force generated by a magnetic field B perpendicular to a wire carrying a current I is
F=ILB
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If we divide both sides for L, we get
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\frac{F}{L}=IB=(9.75 A)(0.81 A)=7.90 N/m
5 0
4 years ago
If you've ever touched a traditional-style lightbulb, you probably noticed that they can get very hot. Does this mean the wires
Art [367]
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