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Vadim26 [7]
3 years ago
5

the angular speed of an automobile engine is increased at a constant rate from 1300rev/min to 2000rev/min in 3s (a) what is its

angular acceleration in revolutions per minute squared ​
Physics
1 answer:
GalinKa [24]3 years ago
8 0

Answer:

please find attached pdf

Explanation:

Download pdf
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Fl-19 in florida, if your pwc is equipped with an engine cut-off lanyard, what must you do with it?
melamori03 [73]

Answer: Attach it to clothing, personal flotation device or the person's person.

Explanation:

This particular Question or problem has to do with the rules and regulations or laws governing the use of Personal Watercraft(PWC) in the state of Florida in the United States of America. Hence, one of the rules that is applicable to the use of boats and waterways or the use of personal watercraft in Florida is that in florida, if ones pwc is equipped with an engine cut-off lanyard the person operating it must ATTACH IT TO THE CLOTHING, PERSONAL FLOATATION DEVICE IR THE OPERATORS' PERSON.

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3 years ago
Your environment can play a role in whether or not a specific gene is expressed
Hatshy [7]
I don't think so. How are you supposed to write the answer?
4 0
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Experiment: Limestone
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7 0
3 years ago
The valve in the exit pipe is closed . The density of water is 1000kg / m and the gravitational force on free fall of water is 1
Stels [109]

Answer:

300000

Explanation:

p=30x10x1000=30000pascal

7 0
3 years ago
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A 74 kg firefighter slides, from rest, 4.9 m down a vertical pole. (a) If the firefighter holds onto the pole lightly, so that t
In-s [12.5K]

Answer:

Her speed is 9.8 meter per second

Explanation:

Newton's second law states that acceleration (a) is related with force (F) by:

\sum\overrightarrow{F}=m\overrightarrow{a} (1)

Here the only force acting on the firefighter is the weight F=mg so (1) is:

mg=ma

Solving for a:

a=g

Now with the acceleration we can use the Galileo's kinematic equation:

Vf^{2}=Vo^{2}+2a\varDelta x (2)

With Vf the final velocity, Vo the initial velocity and Δx the displacement, because the firefighter stars from rest Vo=0 so (2) is:

Vf^{2}=2a\varDelta x

Solving for Vf

Vf=\sqrt{2g\varDelta x}=\sqrt{2(9.81)(4.9)}

Vf=9.8\frac{m}{s}

6 0
3 years ago
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