Answer:
The expected value of X is
and the variance of X is 
The expected value of Y is
and the variance of Y is 
Step-by-step explanation:
(a) Let X be a discrete random variable with set of possible values D and probability mass function p(x). The expected value, denoted by E(X) or
, is

The probability mass function
of X is given by

Since the bus driver is equally likely to drive any of the 4 buses, the probability mass function
of Y is given by

The expected value of X is
![E(X)=\sum_{x\in [28,32,42,44]} x\cdot p_{X}(x)](https://tex.z-dn.net/?f=E%28X%29%3D%5Csum_%7Bx%5Cin%20%5B28%2C32%2C42%2C44%5D%7D%20x%5Ccdot%20p_%7BX%7D%28x%29)

The expected value of Y is
![E(Y)=\sum_{x\in [28,32,42,44]} x\cdot p_{Y}(x)](https://tex.z-dn.net/?f=E%28Y%29%3D%5Csum_%7Bx%5Cin%20%5B28%2C32%2C42%2C44%5D%7D%20x%5Ccdot%20p_%7BY%7D%28x%29)

(b) Let X have probability mass function p(x) and expected value E(X). Then the variance of X, denoted by V(X), is
![V(X)=\sum_{x\in D} (x-\mu)^2\cdot p(x)=E(X^2)-[E(X)]^2](https://tex.z-dn.net/?f=V%28X%29%3D%5Csum_%7Bx%5Cin%20D%7D%20%28x-%5Cmu%29%5E2%5Ccdot%20p%28x%29%3DE%28X%5E2%29-%5BE%28X%29%5D%5E2)
The variance of X is
![E(X^2)=\sum_{x\in [28,32,42,44]} x^2\cdot p_{X}(x)](https://tex.z-dn.net/?f=E%28X%5E2%29%3D%5Csum_%7Bx%5Cin%20%5B28%2C32%2C42%2C44%5D%7D%20x%5E2%5Ccdot%20p_%7BX%7D%28x%29)


The variance of Y is
![E(Y^2)=\sum_{x\in [28,32,42,44]} x^2\cdot p_{Y}(x)](https://tex.z-dn.net/?f=E%28Y%5E2%29%3D%5Csum_%7Bx%5Cin%20%5B28%2C32%2C42%2C44%5D%7D%20x%5E2%5Ccdot%20p_%7BY%7D%28x%29)


It's "commutative property," which says that (for addition/multiplication) order of the operator doesn't matter. For eg, 3 * 5 = 5 * 3.
Associative property (again, of multiplication and addition) means that it doesn't matter how you solve an expression if the same operand is used and some numbers are grouped. For eg. 3 * (5 * 4) = (3 * 5) * 4.
Answer:
<u>brainliest plzzzzzzzz</u>
120
Step-by-step explanation:
LCM=1320
(GDC) HCF=12
Another no.=132
let second no. be =A
According to question
First no.×Second no.=HCF×LCM
132×A=12×1320
132×A=15840
A=15840/132
A=120
Other no. is 120
Answer:
Step-by-step explanation:
1) the triangle is a right angle triangle.
From the given right angle triangle,
With 67° as the reference angle,
x represents the adjacent side of the right angle triangle.
17 represents the opposite side of the right angle triangle.
To determine x, we would apply
the Tangent trigonometric ratio.
Tan θ = opposite side/adjacent side.
Therefore,
Tan 67 = 17/x
xTan 67 = 17
x = 17/Tan 67
x = 17/2.3559
x = 7.22
2) From the given right angle triangle, with 24° as the reference angle,
x represents the opposite side of the right angle triangle.
12 represents the adjacent side of the right angle triangle.
To determine x, we would apply
the Tangent trigonometric ratio.
Tan θ = opposite side/adjacent side.
Therefore,
Tan 24 = x/12
x = 12Tan 24
x = 12 × 0.4452
x = 5.34