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Pavlova-9 [17]
2 years ago
10

When solutions of sodium sulfide and copper(ii) sulfate are mixed, a precipitate of copper(ii) sulfide is formed. what is the ne

t ionic equation for this reaction?
Chemistry
1 answer:
ozzi2 years ago
5 0

When solutions of sodium sulfide and copper(ii) sulfate are mixed, a precipitate of copper(ii) sulfide is formed. The net ionic equation for this reaction is Cu⁺² (aq) + S⁻² (aq) → CuS (s).

<h3>What is Balanced Chemical Equation ?</h3>

The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.

Now first write the balanced chemical equation

CuSO₄ (aq) + Na₂S (aq)  → CuS(s) + Na₂SO₄ (aq)

Now write the net ionic equation

Cu⁺² (aq) + SO₄⁻² (aq) + 2Na⁺ (aq) + S⁻² (aq) → CuS (s) + 2Na⁺ + SO₄⁻² (aq)

So the net ionic equation is

Cu⁺² (aq) + S⁻² (aq) → CuS (s)

Thus from the above conclusion we can say that When solutions of sodium sulfide and copper(ii) sulfate are mixed, a precipitate of copper(ii) sulfide is formed. The net ionic equation for this reaction is Cu⁺² (aq) + S⁻² (aq) → CuS (s).

Learn more about the Balanced Chemical Equation here: brainly.com/question/26694427

#SPJ4

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Si desea preparar 300 gramos de una solución de azúcar en agua que tenga una concentración de 20% m/m en cuanto gramos de soluto
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Answer:

m_{soluto}=60g

Explanation:

¡Hola!

En este caso, al considerar la unidad de concentración de porcentaje masa/masa, podemos escribir su fórmula como:

\%m/m=\frac{m_{soluto}}{m_{solucion}}*100\%

Podemos identificar la masa de soluto (azúcar) como la incógnita, y resolverla como se muestra a continuación:

m_{soluto}=\frac{\%m/m*m_{solucion}}{100\%}\\\\m_{soluto}=\frac{20\%*300g}{100\%}\\\\m_{soluto}=60g

¡Saludos!

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What is paper chromatography? Calculate the Rr value of a colored dye that traveled 52 mm on a chromatography strip while the so
Karo-lina-s [1.5K]

Answer:

Paper chromatography is a basic technique of chromatography. It consist in the separation of the mixe components using a solvent.

Explanation:

Paper chromatography is a basic technique of chromatography. It consists in the separation of the mixed components using a solvent.

Paper chromatography consists of put some dot of the mix using a glass capillary into a specialized paper, generally made of cellulose, this is called a stationary phase.

Then you put this paper into a camera of glass named, chromatography camera, where previously contain a solvent. The solvent also know as a mobile phase, the type can be defined before the test and involves a study of the kind of the mix, and the compound you want to separate.

The chromatography camera has to be closed all the time during the test, and you can't move at all because the movement of the solvent can alternate the result.

Very often, the solution of the solvent is a mix of different liquid substances with different polarities.

When the stationary phase put into the camera, the solvent starts to move up over the paper, until the separation of the compounds is observable.

the Rf is a value who relates the move of the mobile phase with the move of the distance traveled by the substance tested.

To undersant the paper chromatography, you can watch the images attached.

The first is an image of the chromatography camera.

The second one is an image of a cellulose paper after the chromatography is done. You can watch the dots who indicates the traveling of the compound across the paper.

The third one can show you the evolutions of paper chromatography, from the beginning to the end.

To calculate the Rf value you have to use the equation:

Rf = distance traveled by the substance/distance traveled by the solvent/

<u>Rf = 52mm/81mm =0.64</u>

<u></u>

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2 years ago
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