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Makovka662 [10]
3 years ago
5

how does the gravitational force of attraction between two object having fixed mass vary if the distance between them is tripled

?​
Physics
1 answer:
meriva3 years ago
5 0
If the mass of one of the objects is tripled, then the force of gravity between them is tripled. ... Since gravitational force is inversely proportional to the square of the separation distance between the two interacting objects, more separation distance will result in weaker gravitational forces.
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A ball is moving with velocity 5 m/s in a direction which makes an angle of 30° with horizontal (i.e. with positive x-direction)
klasskru [66]

Answer:

Explanation:

(a)

From the given information:

The initial velocity v_1 = 5 m/s

The direction of the angle θ = 30°

Therefore, the component along the x-axis = v_1 \ cos \ \theta

v_{1 \ x } = 5 \ cos \ 30^0

v_{1x} = 4.33 \ m/s

The component along the y-axis = v_2 { \ sin \  \theta}

v_{1 \ y } = 5 \ sin \ 30^0

v_{1 \ y } = 2.5 \ m/s

To find the final velocity( reflected velocity)

using the same magnitude v_2 = 5 \ m/s

The angle from the x-axis can be \theta_r = 90^0+60^0

= 150°

Thus, the component along the x-axis = v_2  \ cos \theta _r

v_{2x} = - 0.433 \ m/s

The component along the y-axis = v_2 \ sin \theta_r

v_{2y} = 5 \ sin \ 150^0

v_{2y} = 2.5 \ m/s

(b)

The velocity v_1 can be written as in vector form.

v_1 ^{\to}  = v_1 x \hat {i} + v_1 y \hat {j}

v_1 ^{\to}  =4.33 \ \hat {i} +  2.5 \  \hat {j}  ----  (1)

The reflected velocity in vector form can be computed as:

v_2 ^{\to}  = v_2 x \hat {i} + v_2 y \hat {j}

v_2 ^{\to}  =-4.33 \ \hat {i} +  2.5 \  \hat {j}  --- (2)

The change in velocity = v_2 ^{\to} - v_1 ^{\to}

\Delta v ^{\to} = - 4.33 \hat i + 2.5 \hat j - 4.33 \hat i - 2.5 \hat j

\Delta v ^{\to} = - 8.66 \hat  { i }

(c)

The magnitude of change in velocity = | \Delta V |

| \Delta V | = 8.66 m/s

6 0
3 years ago
Help me with this please
Alex787 [66]

Let's use the given equation, F = ma, to find out the force of each of the objects given.

A) F = 5 x 10 = 50 N

B) F = 5 x 20 = 100 N

C) F = 20 x 4 = 80 N

D) F = 20 x 3 = 60 N

The object with the greatest force is object B, with a force of 100 N.

Hope this helps! :)

5 0
4 years ago
Read 2 more answers
A sports car accelerates from rest to 27.8 m/s in 4.80 s. What magnitude force does the 66.0 kg driver experience during the acc
kkurt [141]
Acceleration= change in velocity/time=27.8-0/4.8=5.792 ms⁻²
Force= Mass*acceleration=66*5.792=382.25 N
6 0
4 years ago
A 580-mm long tungsten wire, with a 0.046-mm-diameter circular cross section, is wrapped around in the shape of a coil and used
Bad White [126]

Answer:

N=1.64\times10^{19}

R=19.54\Omega

V=10.28V

Explanation:

By definition I=Q/t, so we can calculate the total charge that went through the filament since we know the electric current and the time. If the charge of one electron is e, then the total charge will be given by Q=Ne. Combining these equations we get the number of electrons as:

N=\frac{Q}{e}=\frac{It}{e}=\frac{(0.526A)(5s)}{1.602\times10^{-19}C}=1.64\times10^{19}

Since the resistivity of tungsten (W) is \rho_W=5.6
\times10^{-8}\Omega m, then resistance can be calculated using the formula:

R=\rho_W\frac{L}{A}=\rho_W\frac{L}{\pi r^2}=(5.6\times10^{-8}\Omega m)\frac{(0.58m)}{\pi (0.000023m)^2}=19.54\Omega

Where we already obtained the radius from the diameter. Finally the Voltage will be given by the formula:

V=RI=(19.54\Omega)(0.526A)=10.28V

3 0
3 years ago
The picture is attached.
VLD [36.1K]

Answer:

C

Explanation:

5 0
3 years ago
Read 2 more answers
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