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MissTica
3 years ago
8

What is the force on an electron in a CRT when it’s moving at 2.5 × 105 meters/second perpendicular to a magnetic field of 1.5 t

eslas? The charge for an electron is -1.6 × 10-19 coulombs.

Physics
1 answer:
Firdavs [7]3 years ago
4 0
F = Magnetic Force
B = Magnetic Field
V = Velocity

*The vectors from the photo you get doing the left-hand rule.

The magnetic force is always perpendicular to the magnetic field.

And as told in the statement, the electron is moving perpendicular to a magnetic field, that is, the Velocity forms an 90 degree angle / Right angle with the magnetic field.

The formula to find the Magnetic Force is:

f = |q| \times v \times b \times sin \: \theta

Where "q" is the Charge and the sin theta is the angle formed by the Velocity and Magnetic Field, in this case it's 90°. Sin 90° = 1.

f = |- 1.6 \times {10}^{ - 19} | \times 2.5 \times {10}^{5} \times 1.5 \times 1 \\ f = 6 \times {10}^{ - 19 + 5} \\ f = 6 \times {10}^{ - 14} \: newtons
Newton (N) = C x m/s x T = (C x m x T)/s

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PLEASEEE HELP, thank you :)
telo118 [61]

Answer:

The answer is B.

Explanation:

Given that the <em>current </em>(Ampere) in a series circuit is same so we can ignore it. We can assume that the total voltage is 60V and all the 3 resistance are different, 20Ω, 40Ω and 60Ω. So first, we have to find the total resistance by adding :

Total resistance = 20Ω + 40Ω + 60Ω

= 120Ω

Next, we have to find out that 1Ω is equal to how many voltage by dividing :

120Ω = 60V

1Ω = 60V ÷ 120

1Ω = 0.5V

Lastly, we have to calculate the voltage at R1 so we have to multiply by 20 (R1) :

1Ω = 0.5V

20Ω = 0.5V × 20

20Ω = 10V

8 0
3 years ago
HURRY 20 POINTS <br><br><br> Why is it important to include exercise in your daily routine?
Sedbober [7]

Explanation:

it can improve muscle strength and boost your endurance.

it also delivers oxygen and nutrients to your tissues

3 0
2 years ago
In an Atwood's machine, one block has a mass of 602.0 g, and the other a mass of 717.0 g. The pulley, which is mounted in horizo
Wittaler [7]

Answer:

The acceleration of the both masses is 0.0244 m/s².

Explanation:

Given that,

Mass of one block = 602.0 g

Mass of other block = 717.0 g

Radius = 1.70 cm

Height = 60.6 cm

Time = 7.00 s

Suppose we find  the magnitude of the acceleration of the 602.0-g block

We need to calculate the acceleration

Using equation of motion

s=ut+\dfrac{1}{2}at^2

Where, s = distance

t = time

a = acceleration

Put the value into the formula

60.0\times10^{-2}=0+\dfrac{1}{2}\times a\times(7.00)^2

a=\dfrac{60.0\times10^{-2}\times2}{(7.00)^2}

a=0.0244\ m/s^2

Hence, The acceleration of the both masses is 0.0244 m/s².

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3 years ago
A string is tied between two posts separated by 2.4 m. When the string is driven by an oscillator at frequency 567 Hz, 5 points
Alex787 [66]

Explanation:

The given data is as follows.

       Length (l) = 2.4 m

       Frequency (f) = 567 Hz

Formula to calculate the speed of a transverse wave is as follows.

                  f = \frac{5}{2l} \times v

Putting the gicven values into the above formula as follows.

                  f = \frac{5}{2l} \times v

                 567 Hz = \frac{5}{2 \times 2.4 m} \times v

                      v = 544.32 m/s

Thus, we can conclude that the speed (in m/s) of a transverse wave on this string is 544.32 m/s.

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3 years ago
What is your opinion on abortion?
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Ratio

L nobody cares and bozo

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