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Ber [7]
3 years ago
15

A 3.0 M HCl(aq) solution contains a total of

Chemistry
2 answers:
goblinko [34]3 years ago
6 0
Molarity = number of moles / volume in liters solution

Answer (3)

hope this helps!


Karolina [17]3 years ago
5 0

Answer : The correct option is, (3) 3.0 moles of HCl per liter of solution

Explanation :

Molarity : It is defined as the number of moles of solute present in one liter of the solution. The S.I unit of molarity is mole per liter.

It is represented as,

Molarity=\frac{\text{Moles of solute}}{V_{solution}(L)}

where,

V = volume of solution in liter

As we are given 3.0 M HCl(aq) solution this means that 3.0 moles of HCl present in one liter of solution.

Hence, a 3.0 M HCl(aq) solution contains a total of 3.0 moles of HCl per liter of solution.

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Which statement is correct for the element of proton number 19?
BlackZzzverrR [31]

Answer:

D

Explanation:

From periodic table : proton number 19  corresponds to K  (potassium)

  which is very reactive with water

8 0
2 years ago
What happens to the cell membrane during exocytosis?
Cloud [144]

Answer:

Endocytosis and Exocytosis: Differences and Similarities

ARTICLE Apr 28, 2020

by Nicole Gleichmann

Endocytosis and Exocytosis: Differences and Similarities

Endocytosis and exocytosis are the processes by which cells move materials into or out of the cell that are too large to directly pass through the lipid bilayer of the cell membrane. Large molecules, microorganisms and waste products are some of the substances moved through the cell membrane via exocytosis and endocytosis.

Why is bulk transport important for cells?

Cell membranes are semi-permeable, meaning they allow certain small molecules and ions to passively diffuse through them. Other small molecules are able to make their way into or out of the cell through carrier proteins or channels.

But there are materials that are too large to pass through the cell membrane using these methods. There are times when a cell will need to engulf a bacterium or release a hormone. It is during these instances that bulk transport mechanisms are needed.

Endocytosis and exocytosis are the bulk transport mechanisms used in eukaryotes. As these transport processes require energy, they are known as active transport processes.

Vesicle function in endocytosis and exocytosis

During bulk transport, larger substances or large packages of small molecules are transported through the cell membrane, also known as the plasma membrane, by way of vesicles – think of vesicles as little membrane sacs that can fuse with the cell membrane.

Cell membranes are comprised of a lipid bilayer. The walls of vesicles are also made up of a lipid bilayer, which is why they are capable of fusing with the cell membrane. This fusion between vesicles and the plasma membrane facilitates bulk transport both into and out of the cell.

What is endocytosis? Endocytosis definition and purposes

Endocytosis is the process by which cells take in substances from outside of the cell by engulfing them in a vesicle. These can include things like nutrients to support the cell or pathogens that immune cells engulf and destroy.

Endocytosis occurs when a portion of the cell membrane folds in on itself, encircling extracellular fluid and various molecules or microorganisms. The resulting vesicle breaks off and is transported within the cell.

8 0
2 years ago
How many moles of MgCl2 are there in 343 g of the compound?
mash [69]

The answer is 3.592?

6 0
3 years ago
The theoretical yield of ammonia in an industrial synthesis was 550 kg, but only 480 kg was obtained. What was the percentage yi
Klio2033 [76]

We know that when calculating percent yield, we use the equation:


Percent yield=\frac{Actual yield (A)}{Theoretical yield (T)}


Since the quantities that we are given in the question are equal, we can just directly divide them to find percent yield:


Percentyield=\frac{480kg}{550kg} =0.8727*100=87.27


So now we know that the percent yield of the synthesis is 87.27%.

7 0
3 years ago
Determine the AMOUNT OF NO2, LIMITING REACTANT, AND THE AMOUNT AND NAME OF EXCESS REACTANT.
zepelin [54]

Answer:

balanced equation mole ratio 5 2 mol NO/1 mol O2

10.00 g O2 3 1 mol O2/32.00 g O2 5 0.3125 mol O2

20.00 g NO 3 1 mol NO/30.01 g NO 5 0.6664 mol NO

actual mole ratio 5 0.6664 mol NO/0.3125 mol O2 5 2.132 mol NO/1.000 mol O2

Because the actual mole ratio of NO:O2 is larger than the balanced equation mole

ratio of NO:O2, there is an excess of NO; O2 is the limiting reactant.

Mass of NO used 5 0.3125 mol O2 3 2 mol NO/1 mol O2 5 0.6250 mol NO

0.6250 mol NO 3 30.01 g NO/1 mol NO 5 18.76 g NO

Mass of NO2 produced 5 0.6250 mol NO2 3 46.01 g NO2/1 mol NO2 5 28.76 g NO2

Excess NO 5 20.00 g NO 2 18.76 g NO 5 1.24 g N

Explanation:

3 0
2 years ago
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