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3 years ago

Classify the following as an element, compound, homogeneous mixture, or heterogeneous mixture:

Chemistry

1 answer:

zysi [14]3 years ago

5 0

CO2 is classified as a compound

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It is found that a gas undergoes a first-order decomposition reaction. If the rate constant for this reaction is 8.1 x 10-2 /min

kap26 [50]

Answer:

28.43 min

Explanation:

Using integrated rate law for first order kinetics as:

$[A_t]=[A_0]e^{-kt}$

Where,

$[A_t]$ is the concentration at time t

$[A_0]$ is the initial concentration

Given that:

The rate constant, k = $8.1\times 10^{-2}$ min⁻¹

Initial concentration $[A_0]$ = 0.1 M

Final concentration $[A_t]$ = $1.0\times 10^{-2}$ M

Time = ?

Applying in the above equation, we get that:-

$1.0\times 10^{-2}=0.1e^{-8.1\times 10^{-2}\times t}$

$0.1e^{-8.1\times \:10^{-2}t}=10^{-2}$

$e^{-8.1\times \:10^{-2}t}=\frac{1}{10}$

$\ln \left(e^{-8.1\times \:10^{-2}t}\right)=\ln \left(\frac{1}{10}\right)$

$t=28.43\ min$

3 0

3 years ago

A Cyclist rode at an average speed of 10mph for 15 miles. how long was the ride

Setler79 [48]

Hey there Abigaildonaimor,

A cyclist rode at an average speed of 10mph for 15 miles. How long was the ride?

Answer:

Time = Distance / Rate
= 15 miles / 10mph
= 1.5 hours

Hope this helps :D

~Natasha♥

6 0

3 years ago

Read 2 more answers

What is the mean free path for the molecules in an ideal gas when the pressure is 100 kPa and the temperature is 300 K given tha

sladkih [1.3K]

Answer:

The mean free path = 2.16*10^-6 m

Explanation:

Given:

Pressure of gas P = 100 kPa

Temperature T = 300 K

collision cross section, σ = 2.0*10^-20 m2

Boltzmann constant, k = 1.38*10^-23 J/K

To determine:

The mean free path, λ

Calculation:

The mean free path is related to the collision cross section by the following equation:

$\lambda =\frac{1}{n\sigma }------(1)$

where n = number density

$n = \frac{P}{kT}-----(2)$

Substituting for P, k and T in equation (2) gives:

$n = \frac{100,000 Pa}{1.38*10^{-23} J/K*300K} =2.42*10^{25}\ m^{3}$

Next, substituting for n and σ in equation (1) gives:

$\lambda =\frac{1}{2.42*10^{25}m^{-3}* .0*10^{-20}m^{2}}=2.1*10^{-6}m$

6 0

3 years ago

How many moles are there in 2.75L of a 2.0M solution

gtnhenbr [62]

5.5 moles
2.0=x/2.75
2.0*2.75= x/2.75 (2.75)
5.5=x

7 0

3 years ago

Hey sample of helium occupies 235 mL at 788 tour and 25°C. If the sample is condensed into a 0.115 L flask what will be the new

7nadin3 [17]

the system is in constant temperature

so it follows Boyle's law

i.e.P1V1=P2P2

where P1=initial pressure=788 tour

P2=final pressure= ?

V1=initial volume=235 ml

V2=final volume=0.115 ml

3 0

3 years ago