Classify the following as an element, compound, homogeneous mixture, or heterogeneous mixture:

Ammonia will decompose into nitrogen and hydrogen at high temperature. An industrial chemist studying this reaction fills a 500.

yaroslaw [1]

Answer:

12. is the pressure equilibrium constant for the decomposition of ammonia at the final temperature of the mixture.

Explanation:

$2NH_3(g)\rightleftharpoons N_2(g)+3H_2(g)$

initially

3.0 atm 0 0

At equilibrium

(3.0-2p) p 3p

Equilibrium partial pressure of nitrogen gas = p = 0.90 atm

The expression of a pressure equilibrium constant will be given by :

$K_p=\frac{p_{N_2}\times (p_{H_2})^3}{(p_{NH_3})^2}$

$K_p=\frac{p\times (3p)^3}{(3.0-2p)^2}$

$=\frac{0.90 atm\times (3\times 0.90 atm)^3}{(3.0-2\times 0.90 atm)^2}$

$K_p=12.30\approx 12.$

12. is the pressure equilibrium constant for the decomposition of ammonia at the final temperature of the mixture.

3 0

3 years ago

Consider the reaction: N2(g) 2 O2(g)N2O4(g) Write the equilibrium constant for this reaction in terms of the equilibrium constan

Valentin [98]

Answer : The equilibrium constant for this reaction is, $K=\frac{(K_b)^2}{K_a}$

Explanation :

The given main chemical reaction is:

$N_2(g)+2O_2(g)\rightarrow N_2O_4(g)$ ; $K$

The intermediate reactions are:

(1) $N_2O_4(g)\rightarrow 2NO_2(g)$ ; $K_a$

(2) $\frac{1}{2}N_2(g)+O_2(g)\rightarrow NO_2(g)$ ; $K_b$

We are reversing reaction 1 and multiplying reaction 2 by 2 and then adding both reaction, we get:

(1) $2NO_2(g)\rightarrow N_2O_4(g)$ ; $\frac{1}{K_a}$

(2) $N_2(g)+2O_2(g)\rightarrow 2NO_2(g)$ ; $(K_b)^2$

Thus, the equilibrium constant for this reaction will be:

$K=\frac{1}{K_a}\times (K_b)^2$

$K=\frac{(K_b)^2}{K_a}$

Thus, the equilibrium constant for this reaction is, $K=\frac{(K_b)^2}{K_a}$

5 0

3 years ago

Help me i could fail this

Alina [70]

Answer:

1231231234124

Explanation:

3213+123124124

5 0

3 years ago

Read 2 more answers

Are watches considered as compound machines?

Alisiya [41]

Yes. They are called compound machines because two or more simple machines were combined to create it.

5 0

3 years ago

Balance the following

olga55 [171]

Answer:

Your coefficients (the numbers in front of the molecule) will be the following from left to right.

1. 1 - 2 - 1 - 2

2. 2 - 1 - 2 - 2 - 1

3. 2 - 4 - 1

4. 2 - 4 - 3

5. 2 - 2 - 2 - 1

6. 1 - 1 - 1

7. 2 - 1 - 2

8. 3 - 1 - 2 - 3

9. 3 - 1 - 2 - 3

10. 2 - 1 - 1 - 1

Explanation:

To balance this equations first count how many times an element is on each side and then see what needs to be changed in order to balance them.

8 0

1 year ago