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____ [38]
3 years ago
7

What major component of water affects most its properties?

Chemistry
1 answer:
Alona [7]3 years ago
8 0

Answer:

C. polarity

Explanation:

Water is polar that is why it is a universal solvent.

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What it’s used to determine the number of each atom in an ionic formula
Gala2k [10]

Answer:

If the electronegativity difference is greater than 2.0, then the bond is ionic.

Explanation:

For ex:

Na has the electronegativity of 0.93

Cl has the electronegativity of 3.16

we subtract 3.16-0.93

We have 2.23 electronegativity difference between Na and Cl

because 2.23 > 2.0

therefore NaCl compound has an ionic bond.  

6 0
3 years ago
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What is ion exchange ​
dolphi86 [110]

Answer:

ion exchange is the exchange of ions of the same charge between an insoluble solid and a solution in contact with it, used in water-softening and other purification and separation processes.

Explanation:

hope this helped !

3 0
3 years ago
A certain sample of a liquid has a mass of 42 grams and a volume of 35 centimeters3. What is the density of the liquid? The dens
Xelga [282]

Density of liquid= \frac{mass of liquid}{volume of liquid}.

so, density of liquid= \frac{42 gm}{35 cm^{3} }= 1.2 gm/cm³.

8 0
3 years ago
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Which of these particles are classified as hadrons? a. leptons c. mesons b. electrons d. neutrinos
disa [49]
The answer would be mesons.

Hope this image helps you! :)

4 0
4 years ago
Read 2 more answers
1. (NH)2CrO-
Alex777 [14]

Question:

1. (NH)2CrO

a) Number of moles of H:

b) Number of moles of N:

Answer:

a) Number of moles of H: 2

b) Number of moles of N: 2

Explanation:

The  (NH)_2CrO is ammonium Chromate which is monoclinic and yellow Crystal that is formed due to the reaction of ammonium Hydroxide and ammonium di-chromate. It is used as catalyst, corrosion inhibitor as well as analytical inhibitors.

Question:

2. Ag.SO.

a) Molar Mass:

b) Percent Composition of Ag:

c) Percent Composition of S:

d) Percent Composition of O:​

Answer:

a) Molar Mass:   155.93 Kg

b) Percent Composition of Ag:   69%

c) Percent Composition of S:  20.5%

d) Percent Composition of O:​ 10.2%

Explanation:

Molar mass =   molar mass of Ag +  molar mass of S +  molar mass of O  

=>107.87+32.06+16

=> 155.93 Kg

Percent Composition of Ag

= \frac{ \text{mass due  to Ag}}{\text {total molar mass}}  \times 100

= \frac{107.87}{155.93} \times 100

= 0.69 \times 100

= 69%

Percent Composition of S:

= \frac{ \text{mass due  to S}}{\text {total molar mass}}  \times 100

=\frac{32.06}{155.93} \times 100

= 0.205 \times 100

= 20.5%

Percent Composition of O:

= \frac{ \text{mass due  to O}}{\text {total molar mass}}  \times 100

= \frac{16.00}{155.93} \times 100

= 0.102 \times 100

= 10.2%

3 0
3 years ago
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