The acceleration of gravity on Moon B is D) 0.25 m/s2
Explanation:
The data listed in the problem are not clear: find them in the table attached.
The acceleration of gravity on a planet is given by the following equation:
where:
is the gravitational constant
M is the mass of the planet
R is the radius of the planet
Here we want to find the acceleration of gravity on the surface of Moon B, which has the following data:
(mass)
(radius)
And substituting into the equation, we find:
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True, the wavelength dies down due to high frequency and low amptitude.
The wavelength of the radio wave is 0.303 m.
<h3>
Wavelength</h3>
The wavelength of the wave is the distance traveled by the wave.
c = fλ
where;
- c is speed of light = 3 x 10⁷ m/s
- f is frequency
- λ is wavelength
λ = c/f
λ = (3 x 10⁷ ) / (99 x 10⁶)
λ = 0.303 m
Thus, the wavelength of the radio wave is 0.303 m.
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Answer:
The distance between two posts
Explanation:
As the students have already measured the amount of time necessary for the wave to oscillate up and down that is on the string between two posts,They have to measure the speed of the wave.
ie v=fλ
<em>They have to measure distance between the posts.
</em>
Because wavelength is equal to the distance between the posts ie full length of string.
The frequency of the wave is calculated by
f=
1/T
Where is the time period which the students have calculated ie the amount of time taken to oscillate up and down,
Thus the wave speed is calculated using formula
v=λ/T
you need to use hours to make it easy to convert to m/s. Change 15 minutes to hours
Note distance is in km so change the time to hours to get km/hour
1 hour = 60mins so 15 minutes will be 0.25 hours
10/0.25 = 40 km/ hour
To change that to m/second, change km to meters and hour to second
it will be (40x1000) meters /3600seconds
11.1111 m/s
