Answer:
The height of the hill is, h = 38.42 m
Explanation:
Given,
The horizontal velocity of the soccer ball, Vx = 15 m/s
The range of the soccer ball, s = 42 m
The projectile projected from a height is given by the formula
S = Vx [Vy + √(Vy² + 2gh)] / g
Therefore,
h = S²g/2Vx² (Since Vy = 0)
Substituting the values
h = 42² x 9.8/ (2 x 15²)
= 38.42 m
Hence, the height of the hill is, h = 38.42 m
Well i’d love to answer your question but its missing some information. firstly the earth is within the milky way galaxy so something cannot travel “from” but if you said “through” the answer would be 299,792,458 meters a second
Acceleration of gravity is proportional to 1/D² .
('D' is the distance from the Earth's center.)
We need (D / R)² = 9.8
('R' is the Earth's radius.)
D/R = √9.8 = 3.13
Distance from Earth's <u>center</u> = 3.13 R
Distance above Earth's <u>surface</u> = 2.13 R = about 13,570 km =====================================================
<span>Accelerarea de gravitate este proporțională cu 1 / D².
('D este distanța de centrul Pământului.)
Avem nevoie de (D / R) ² = 9,8
('R' este raza Pământului.)</span><span>
D / R = √9.8 = 3,13
Distanța de la <u>centrul</u> Pamantului = 3,13 R
Distanța de deasupra <u>suprafetei</u> Pamantului = 2.13 R = aproximativ <span><em>13,570 km</em></span></span>
