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Daniel [21]
3 years ago
10

Please help !! thank youuu

Mathematics
1 answer:
dolphi86 [110]3 years ago
4 0

Answer:

No, she should have added (6^2) and (8^2) and compared that too (10^2).

Step-by-step explanation:

An easy way to determine if a triangle is right is by using the Pythagorean theorem. The Pythagorean theorem states the following,

a^2 + b^2 = c^2

Where (a) and  (b) are the legs or the sides adjacent to the right angle, and (c) is the hypotenuse or the side opposite the right angle. The hypotenuse is always the largest side in a right triangle.

One can substitute in the given sides and solve to prove that the given triangle with the following side lengths (6, 8, 10) forms a right triangle.

(6)^2 + (8)^2 = (10)^2\\\\36 + 64 = 100\\\\100 = 100

Thus the given triangle is a right triangle because one can apply the Pythagorean theorem to its side lengths.

The mistake that was made in the given problem was that the person in the given situation set up the equation using the wrong sides, and thus got a wrong result. Therefore, one should select the following option as their answer,

No, she should have added (6^2) and (8^2) and compared that too (10^2).

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A student provided the following solution for an equation. What mistake did the student make?
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Answer:

1st choice - 1st line- Distributive property applied incorrectly

Step-by-step explanation:

3(a-2) should be 3a-6

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3 years ago
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D or A

Step-by-step explanation:

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Sean tossed a coin off a bridge into the stream below. The path of the coin can be represented by the equation 2 h tt = − 16t^2+
tekilochka [14]

Answer:

It will take 5.61 seconds for the coin to reach the stream.

Step-by-step explanation:

The height of the coin, after t seconds, is given by the following equation:

h(t) = -16t^{2} + 72t + 100

How long will it take the coin to reach the stream?

The stream is the ground level.

So the coin reaches the stream when h(t) = 0.

h(t) = -16t^{2} + 72t + 100

-16t^{2} + 72t + 100 = 0

Multiplying by (-1)

16t^{2} - 72t - 100 = 0

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this question:

16t^{2} - 72t - 100 = 0

So

a = 16, b = -72, c = -100

\bigtriangleup = (-72)^{2} - 4*16*(-100) = 11584

t_{1} = \frac{-(-72) + \sqrt{11584}}{2*16} = 5.61

t_{2} = \frac{-(-72) - \sqrt{11584}}{2*16} = -1.11

Time is a positive measure, so we take the positive value.

It will take 5.61 seconds for the coin to reach the stream.

3 0
4 years ago
Find [5(cos 330 degrees + I sin 330 degrees)]^3
earnstyle [38]
Given a complex number in the form:
z= \rho [\cos \theta + i \sin \theta]
The nth-power of this number, z^n, can be calculated as follows:

- the modulus of z^n is equal to the nth-power of the modulus of z, while the angle of z^n is equal to n multiplied the angle of z, so:
z^n = \rho^n [\cos n\theta + i \sin n\theta ]
In our case, n=3, so z^3 is equal to
z^3 = \rho^3 [\cos 3 \theta + i \sin 3 \theta ] = (5^3) [\cos (3 \cdot 330^{\circ}) + i \sin (3 \cdot 330^{\circ}) ] (1)
And since 
3 \cdot 330^{\circ} = 990^{\circ} = 2\pi +270^{\circ}
and both sine and cosine are periodic in 2 \pi,  (1) becomes
z^3 = 125 [\cos 270^{\circ} + i \sin 270^{\circ} ]

6 0
4 years ago
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