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2 years ago

PLEASE HELP ASAP ITS DUE SOON!!!!

Mathematics

2 answers:

Mars2501 [29]2 years ago

6 0

Answer:

Step-by-step explanation:

Look at the y axis and find the highest point.

seropon [69]2 years ago

6 0

Answer:

I believe it would be a: y=30; The maximum height...

Step-by-step explanation:

It's where the line would be, and describes exactly where the line of symmetry would be. Hope this helps :)

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vitfil [10]

Hi there!

$\large\boxed{y = 12, x = 3}$

The two trapezoids are similar, so we can determine a common scale factor:

OL/UR = NM/TS

9/3 = 6/2

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Give a 98% confidence interval for one population mean, given asample of 28 data points with sample mean 30.0 and sample standar

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We have a sample of 28 data points. The sample mean is 30.0 and the sample standard deviation is 2.40. The confidence level required is 98%. Then, we calculate α by:

$\begin{gathered} 1-\alpha=0.98 \\ \alpha=0.02 \end{gathered}$

The confidence interval for the population mean, given the sample mean μ and the sample standard deviation σ, can be calculated as:

$CI(\mu)=\lbrack x-Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}},x+Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}}\rbrack$

Where n is the sample size, and Z is the z-score for 1 - α/2. Using the known values:

$CI(\mu)=\lbrack30.0-Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}},30.0+Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}}\rbrack$

Where (from tables):

$Z_{0.99}=2.33$

Finally, the interval at 98% confidence level is:

$CI(\mu)=\lbrack28.94,31.06\rbrack$

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