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3 years ago

Pleaseeee help pretty please

Chemistry

2 answers:

lesantik [10]3 years ago

4 0

Answer:

A object made from iron .

Explanation:

KATRIN_1 [288]3 years ago

4 0

I believe the answer is any object made up of iron since iron has a strong reaction to magnets so it must have a strong connection with the magnetic field

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Please help! Thanks :D

Digiron [165]

Species shown in bold are precipitates.

Ca(NO₃)₂ + 2 KOH → Ca(OH)₂ + 2 KNO₃
Ca(NO₃)₂ + Na₂C₂O₄ → CaC₂O₄ + 2 NaNO₃

Cu(NO₃)₂ + 2 KI → CuI₂ + 2 KI
Cu(NO₃)₂ + 2 KOH → Cu(OH)₂ + 2 KNO₃
Cu(NO₃)₂ + Na₂C₂O₄ → CuC₂O₄ + 2 NaNO₃

Ni(NO₃)₂ + 2 KOH → Ni(OH)₂ + 2 KNO₃
Ni(NO₃)₂ + Na₂C₂O₄ → NiC₂O₄ + 2 NaNO₃

Zn(NO₃)₂ + 2 KOH → Zn(OH)₂ + 2 KNO₃
Zn(NO₃)₂ + Na₂C₂O₄ → ZnC₂O₄ + 2 NaNO₃

A double replacement reaction takes place only if it reduces in the concentration of ions in the solution. For example, the reaction between Ca(NO₃)₂ and KOH produces Ca(OH)₂. Ca(OH)₂ barely dissolves. The reaction has removed Ca²⁺ and OH⁻ ions from the solution.

Some of the reactions lead to neither precipitates nor gases. They will not take place since they are not energetically favored.

Compare the first and last row:

Both Ca(NO₃)₂ and Zn(NO₃)₂ react with KOH. However, between the two precipitates formed, Ca(OH)₂ is more soluble than Zn(OH)₂.

As a result, add the same amount of KOH to two Ca(NO₃)₂ and Zn(NO₃)₂ of equal concentration. The solution that end up with more precipitate shall belong to Zn(NO₃)₂.

Compare the second and third row:

Cu(NO₃)₂ reacts with KI, but Ni(NO₃)₂ does not. Thus, add equal amount of KI to the two unknowns. The solution that forms precipitate shall belong to Cu(NO₃)₂.

8 0

3 years ago

Which sentence best describes the relationship between chlorophyll and the chloroplast?

Viktor [21]

Answer:

chlorophyll is a chemical found in a chloroplast

3 0

3 years ago

Anton van Leeuwenhoek used a microscope to observe

Goshia [24]

B. He was the first person to observe and identify living cells.

4 0

3 years ago

Which pair of ions can form an ionic bond with each other and why? A.Cu and Ag; They are both metal ions.B. S and O; They have l

kap26 [50]

Opposite pairs form ionic bonds, due to this the answer is D - Li and Br; They have unlike charges.

5 0

3 years ago

Read 2 more answers

Ammonia gas will react with oxygen gas to yield nitrogen monoxide gas and water vapor.

ruslelena [56]

Answer:

a) <u>0.168 moles O2</u>

<u>b) </u> <u>9.50 grams O2</u>

<u>d)</u>88.9 %

Explanation:

Step 1: Data given

Molar mass of NH3 = 17.03 g/mol

Molar mass of O2 = 32 g/mol

Molar mass of NO = 30.01 g/mol

Molar mass of H2O = 18.02 g/mol

Step 2: The balanced equation:

4NH3 + 5O2 → 4NO + 6H2O

a. How many moles of ammonia will react with 6.73g of oxygen?

Calculate moles of oxygen = mass O2/ molar mass O2

moles oxygen = 6.73 grams / 32.00 g/mol = 0.210 moles

Calculate moles of NH3

For 4 moles of NH3 we need 5 moles O2 to produce 4 moles NO and 6 moles H2O

For 0.210 moles O2 we need 4/5 *0.210 = <u>0.168 moles O2</u>

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b. If 6.42g of water is produced, how many grams of oxygen gas reacted?

Calculate moles of H2O = 6.42 grams / 18.02 g/mol = 0.356 moles

Calculate moles of O2:

For 4 moles of NH3 we need 5 moles O2 to produce 4 moles NO and 6 moles H2O

For 0.356 moles H2O we'll need 5/6 * 0.356 = 0.297 moles O2

Calculate mass of O2 = moles O2 * molar mass O2

Mass O2 = 0.297 moles O2 * 32.00 g/mol = <u>9.50 grams O2</u>

c. If the reaction uses up 9.43105 g of ammonia, how many kilograms of nitrogen monoxide will be formed?

Calculate moles of ammonia = 9.43105 grams / 17.03 g/mol =0.5538 moles

Calculate moles of NO:

For 4 moles of NH3 we need 5 moles O2 to produce 4 moles NO and 6 moles H2O

For 0.5538 moles of NH3 we'll have 0.5538 moles NO

Calculate mass of NO

Mass NO = 0.5538 moles * 30.01 g/mol = 16.62 grams = <u>0.01662 kg NO</u>

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d. When 2.51 g of ammonia react with 3.76 g of oxygen, 2.27 g of water vapor are produced. What is the percentage yield of water?

<em>Calculate moles of NH3</em> = 2.51 grams / 17.03 g/mol = 0.147 moles

<em>Calculate moles of O2 </em>= 3.76 grams / 32 g/mol = 0.118 moles

<em>Determine the limiting reactant</em>

O2 is the limiting reactant, it will completely be consumed (0.118 moles)

NH3 is in excess. There will react 4/5 * 0.118 = 0.0944 moles

There will remain 0.147 - 0.0944 = 0.0526 moles

<em>Calculate moles H2O</em>: For 0.118 moles O2 we'll have 6/5 * 0.118 = 0.1416 moles H2O

<em>Calculate mass H2O</em> = 0.1416 moles * 18.02 g/mol = 2.552 grams H2O

<em>Calculate % yield</em> = (2.27/2.552)*100 % = <u>88.9 %</u>

4 0

3 years ago