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3 years ago

SOMEONE, PLEASE HELP I WILL GIVE THA BRAINLIST

Mathematics

1 answer:

Tomtit [17]3 years ago

3 0

Answer:

$20.52

Step-by-step explanation:

19 × 8% = 1.52

1.52 + 19 = $20.52

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Square ABCD and square EFGH share a common center on a coordinate plane. is parallel to diagonal . Across how many lines of refl

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Square ABCD and square EFGH will reflect onto themselves across 8 lines of reflection

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3 years ago

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If p = (-1,6) find: Rx-axis (P) HELP NEEDED ASAP

eimsori [14]

Answer:what grade is this for?

Step-by-step explanation:

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2 years ago

2. Write the following in order from least<br> to greatest:<br><br> 0.7, 0.84, 4/5, 82%, 71/100

lutik1710 [3]

Answer:

0.7, 71/100, 4/5, 82%, 0.84

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3 years ago

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Find the value of x. Then find the measure of each labeled angle

34kurt

Answer:

x = 109

Top Right Angle = 109

Bottom Right Angle = 71

Step-by-step explanation:

Notice the two right angles on the left and recognize that the figure is a a quadrilateral (4 sides). That means it adds up to a total of 360 degrees.

(x-38) + x + 90 + 90 = 360

2x + 142 = 360

2x = 218

x = 109

(x - 38) = (109 - 38)

71 degrees for bottom right angle

109 for top right angle

8 0

2 years ago

I really really really need help!!!!

Yakvenalex [24]

For $f$ to be continuous at $x=1$ , you need to have the limit from either side as $x\to1$ to be the same.

$\displaystyle\lim_{x\to1^-}f(x)=\lim_{x\to1^-}(|x-1|+2)=2$
$\displaystyle\lim_{x\to1^+}f(x)=\lim_{x\to1^+}(ax^2+bx)=a+b$

If $a=2$ and $b=3$ , then the limit from the right would be $2+3=5\neq2$ , so the answer to part (1) is no, the function would not be continuous under those conditions.

This basically answers part (2). For the function to be continuous, you need to satisfy the relation $a+b=2$ .

Part (c) is done similarly to part (1). This time, you need to limits from either side as $x\to2$ to match. You have

$\displaystyle\lim_{x\to2^-}f(x)=\lim_{x\to2^-}(ax^2+bx)=4a+2b$
$\displaystyle\lim_{x\to2^+}f(x)=\lim_{x\to2^+}(5x-10)=0$

So, $a$ and $b$ have to satisfy the relation $4a+2b=0$ , or $2a+b=0$ .

Part (4) is done by solving the system of equations above for $a$ and $b$ . I'll leave that to you, as well as part (5) since that's just drawing your findings.

8 0

3 years ago