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Alekssandra [29.7K]
3 years ago
10

Write an equation for an equation with a slope of 1/2 and goes through the point C(−4,3).

Mathematics
2 answers:
Degger [83]3 years ago
6 0
I think the answer should be
C9-3,4
mamaluj [8]3 years ago
4 0

Answer:

c9-3,4)

Step-by-step explanation:

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I need help Please help thank you <3
Llana [10]
The answer is D. 1.601 * 10^9
7 0
3 years ago
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The area of the rectangle shown below is 6x2+11x-7 square units. the length is 2x-1 what is the width
Hitman42 [59]

Answer:

Width is 3x+7 units

Step-by-step explanation:

In the attached file

5 0
3 years ago
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I need help with this someone very smart at math this algebra 2
Mrac [35]

Answer:

value if a =

\frac{5}{4}

Step-by-step explanation:

here's the solution :-

=》

\frac{ 2(\sqrt{m})  {}^{3} }{ \sqrt[4]{m} }

=》

\frac{2(m {}^{ \frac{1}{2}} ) {}^{3} }{ {m}^{ \frac{1}{4} } }

=》

\frac{2 {m}^{ \frac{3}{2} }} { {m}^{ \frac{1}{4} } }

=》

2m {}^{ \frac{3}{2}  -  \frac{1}{4} }

=》

2m {}^{ \frac{6 - 1}{4} }

=》

2m {}^{ \frac{5}{4} }

so, a = 5/4

6 0
3 years ago
Which statements are true about the graph of y ≤ 3x + 1 and y ≥ –x + 2? Check all that apply. 1.The slope of one boundary line i
zloy xaker [14]

Answer:

2.Both boundary lines are solid.

3.A solution to the system is (1, 3)

5.The boundary lines intersect.

Step-by-step explanation:

we have

y\leq 3x+1 ----> inequality A

The solution of the inequality A is the shaded area below the solid line y=3x+1

The slope of the solid line is 3

The point (1,3) is  a solution of inequality A (lie in the shaded area of the solution set)

y\geq -x+2 ----> inequality B

The solution of the inequality B is the shaded area above the solid line y=-x+2

The slope of the solid line is -1

The point (1,3) is a solution of inequality B (lie in the shaded area of the solution set)

The solution of the system of inequalities is the shaded area between the two solids lines

see the attached figure

<u><em>Verify each statement</em></u>

1.The slope of one boundary line is 2

The statement is False

2.Both boundary lines are solid.

The statement is True

3.A solution to the system is (1, 3)

The statement is True

4.Both inequalities are shaded below the boundary lines

The statement is False

5.The boundary lines intersect.

The statement is True

The intersection point is (0.25,1.75)

see the attached figure

7 0
3 years ago
Read 2 more answers
A researcher tests five individuals who have seen paid political ads about a particular issue. These individuals take a multiple
devlian [24]

Answer:

t=\frac{46-40}{\frac{5.148}{\sqrt{5}}}=2.606    

The degrees of freedom are given by:

df=n-1=5-1=4  

The p value wuld be given by:

p_v =2*P(t_{(4)}>2.606)=0.060  

For this case the p value is higher than the significance level so then we can conclude that the true mean is not significantly different from 40

The distribution with the critical values are in the figure attached

Step-by-step explanation:

Information given

48, 41, 40, 51, and 50

The sample mean and deviation can be calculated with these formulas:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

\bar X=46 represent the mean height for the sample  

s=5.148 represent the sample standard deviation

n=5 sample size  

\mu_o =40 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test

Hypothesis to test

We want to test if the true mean for this case is equal to 40, the system of hypothesis would be:  

Null hypothesis:\mu = 40  

Alternative hypothesis:\mu \neq 40  

The statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing we got:

t=\frac{46-40}{\frac{5.148}{\sqrt{5}}}=2.606    

The degrees of freedom are given by:

df=n-1=5-1=4  

The p value wuld be given by:

p_v =2*P(t_{(4)}>2.606)=0.060  

For this case the p value is higher than the significance level so then we can conclude that the true mean is not significantly different from 40

The distribution with the critical values are in the figure attached

6 0
3 years ago
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