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masya89 [10]
3 years ago
5

1. Faça as transformações:

Physics
1 answer:
zhannawk [14.2K]3 years ago
3 0

Answer:

seconds (s) = hours (h) *3,600 ; h = \frac{s}{3,600} \\g = kg * 1,000; kg = \frac{g}{1,000} \\cm = \frac{m}{100};m = cm * 100

1. a) 0.5 h = 1,800 s

  h) 20 cm = 0.2 m

  b) 2.0 h = 7,200 s

   i) 5.0 kg = 5,000 g

  c) 3.5 h = 12,600 s

  j) 1.5 kg = 1,500 g

  d) 1/4 h = 900 s

  k) 450.0 g = 0.45 kg

  e) 3.0 m = 300 cm

   l) 20.0 g = 0.02 kg

  f) 2.5 m = 250 cm

  m) 500.0 g = 0.5 kg

   g) 0.5 m = 500 mm

   n) 1000.0 g = 1 kg

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Answer:

A

Explanation:

3 0
2 years ago
15) A 1720 kg car accelerates at a rate of 3.0 m/s2. How much force is the car's engine producing? (use the formula F=ma
Anastasy [175]

Answer:

<h3>The answer is 5160 N</h3>

Explanation:

To find the force acting on an object given it's mass and acceleration we use the formula

<h3>Force = mass × acceleration</h3>

From the question

mass = 1720 kg

acceleration = 3.0 m/s²

We have

Force = 1720 × 3

We have the final answer as

<h3>5160 N</h3>

Hope this helps you

4 0
3 years ago
Read 2 more answers
How long does it take an airplane to fly 1500 miles of it maintains a speed of 600 miles per hour?
prisoha [69]
2.5 hours. divide 15000 by 600




7 0
3 years ago
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An electric furnace is to melt 40 kg of aluminium/hour. The initial temperature of aluminium is 32°C. Given that aluminium has s
gizmo_the_mogwai [7]

Answer:

Part a)

P = 13.93 kW

Part b)

R = 8357.6 Cents

Explanation:

Part A)

heat required to melt the aluminium is given by

Q = ms\Delta T + mL

here we have

Q = 40(950)(680 - 32) + 40(450 \times 10^3)

Q = 24624 kJ + 18000 kJ

Q = 42624 kJ

Since this is the amount of aluminium per hour

so power required to melt is given by

P = \frac{Q}{t}

P = \frac{42624}{3600} kW

P = 11.84 kW

Since the efficiency is 85% so actual power required will be

P = \frac{11.84}{0.85} = 13.93 kW

Part B)

Total energy consumed by the furnace for 30 hours

Energy = power \times time

Energy = 13.93 kW\times 30 h

Energy = 417.9 kWh

now the total cost of energy consumption is given as

R = P \times 20 \frac{Cents}{kWh}

R = 417.9 kWh\times  20 \frac{cents}{kWh}

R = 8357.6 Cents

3 0
3 years ago
The distance between two planets is 1600 km. How much time would the light
Snowcat [4.5K]

Answer:

5.33*10^-3 seconds

Explanation:

c = d/t

c = speed of light constant (3.0*10^5 km/s)

d = distance (1600 km)

t = ?

3.0*10^5 = 1600/t

t = 1600/3.0*10^5

t = 5.33*10^-3 seconds

I hope this helped! :)

6 0
3 years ago
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