I can say that the kinetic energy after the collision is less than it was before the collision. I can say this with confidence because you've said that some energy was used to deform the car, plus there was energy lost from the system in the form of heat.
Galaxy M33 is classified as a Triangulum normal spiral.
The galaxy M33 is the third largest galaxy in the Local Group after M31 and the Milky Way. The galaxy M33 has a moderate-sized central bulge and two spiral arms that emerge directly out of the bulge and wrap around in rather poorly defined arcs with many cross-connections between the arms.
This spiral galaxy is located in the triangle shaped constellation earning a pet name as triangular galaxy. This galaxy star formation rate is ten times higher than average found in Andromeda galaxy. It has relatively bright apparent. This galaxy was given by Charles Messier and he classified it as Triangulum normal spiral.
Learn more about galaxy here:
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The gravitational force of the shell exerts is 4.25m x 10¯¹² N.
We need to know about gravitational force to solve this problem. The gravitational force is the force caused by two masses of objects. The magnitude of gravitational force can be determined as
F = G.m1.m2 / R²
where F is the gravitational force, G is the gravitational constant (6.674 × 10¯¹¹ Nm²/kg²), m1 and m2 are the mass of the object and R is the radius.
From the question above, we know that
m1 = 1.6 kg
m2 = m
R = 5.01 m
By substituting the following parameters, we get
F = G.m1.m2 / R²
F = 6.674 × 10¯¹¹ . 1.6 . m / 5.01²
F = 4.25m x 10¯¹² N
where m is the mass of the shell
For more on gravitational force at: brainly.com/question/19050897
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Answer:
Net Force Formula: F1+F2+F3...+FN
*(MAKE SURE YOU MAKE NOTE OF THE NEGATIVE FORCES AND SUBTRACT THEM!)*
Explanation:
Top left: 17N+25N+25N-42N= 25N
Top right: 65N+200N-65N-150N-200N= 150N
Bottom left: 189N+123N+284N-96N-188N-312N= 0N
Bottom right: 34N+77N-12N-34N= 65N
I hope this helps! :))
m = mass of the roller coaster = 500 kg
h = height of the hill = 80 m
v = speed of the roller coaster at the bottom of the hill = ?
using conservation of energy
kinetic energy at the bottom of the hill = potential energy at the top of hill
(0.5) m v² = m g h
(0.5) v² = g h
inserting the values
(0.5) v² = (9.8) (80)
v = 39.6 m/s
hence the speed at the bottom comes out to be 39.6 m/s
