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Readme [11.4K]
3 years ago
6

Young's experiment is performed with light of wavelength 502 nm from excited helium atoms. Fringes are measured carefully on a s

creen 1.20 m away from the double slit, and the center of the 20th fringe (not counting the central bright fringe) is found to be 10.2 mm from the center of the central bright fringe. What is the separation of the two slits?
Physics
1 answer:
PSYCHO15rus [73]3 years ago
8 0

Answer:

Explanation:

wave length of light λ = 502 nm

screen distance D = 1.2 m

width of one fringe = 10.2 mm / 20

= .51 mm

fringe width = λ D / a  , a is separation of slits

Puting the values given

.51 x 10⁻³ =  502 x 10⁻⁹ x 1.2 / a

a = 502 x 10⁻⁹ x 1.2 / .51 x 10⁻³

= 1181.17 x 10⁻⁶ m

1.18 x 10⁻³ m

= 1.18 mm .

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Answer:

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Why isn't Coulomb's law valid for dielectric objects, even if they are spherically symmetrical?
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When a rubber ball dropped from rest bounces off the floor, its direction of motion is reversed becaue
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8 0
3 years ago
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A 90 kg person stands at the edge of a stationary children's merry-go-round at a distance of 5.0 m from its center. The person s
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Answer:

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3 years ago
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