First, balance the reaction:
_ KClO₃ ==> _ KCl + _ O₂
As is, there are 3 O's on the left and 2 O's on the right, so there needs to be a 2:3 ratio of KClO₃ to O₂. Then there are 2 K's and 2 Cl's among the reactants, so we have a 1:1 ratio of KClO₃ to KCl :
2 KClO₃ ==> 2 KCl + 3 O₂
Since we start with a known quantity of O₂, let's divide each coefficient by 3.
2/3 KClO₃ ==> 2/3 KCl + O₂
Next, look up the molar masses of each element involved:
• K: 39.0983 g/mol
• Cl: 35.453 g/mol
• O: 15.999 g/mol
Convert 10 g of O₂ to moles:
(10 g) / (31.998 g/mol) ≈ 0.31252 mol
The balanced reaction shows that we need 2/3 mol KClO₃ for every mole of O₂. So to produce 10 g of O₂, we need
(2/3 (mol KClO₃)/(mol O₂)) × (0.31252 mol O₂) ≈ 0.20835 mol KClO₃
KClO₃ has a total molar mass of about 122.549 g/mol. Then the reaction requires a mass of
(0.20835 mol) × (122.549 g/mol) ≈ 25.532 g
of KClO₃.
Noise does not affect the digital signal making it more reliable
Answer:
Option B
Change in entropy of the process is 
Explanation:
The entropy of a system is a measure of the degree of disorderliness of the system.
The entropy of a system moving from process 1 to 2 is given as
recall from first law, 
hence we have, 
since the process is isothermal, 
this gives us 
integrating within the limits of 1 and 2, will give us
also from ideal gas laws,
hence we have 
This makes the correct option B
Answer:
Streams need vitality to move material, and levels of vitality change as the waterway moves from source to mouth.
At the point when vitality levels are high, huge rocks and stones can be moved. Vitality levels are generally higher close to a waterway's source, when its course is steep and its valley slender. Vitality levels rise considerably higher in the midst of flood.
At the point when vitality levels are low, just little particles can be moved (assuming any). Vitality levels are most reduced when speed drops as a waterway enters a lake or ocean (at the mouth).
