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crimeas [40]
3 years ago
15

12) Write the equation of a rational function

Mathematics
1 answer:
aev [14]3 years ago
5 0

Answer:

\frac{4(x - 5)(x + 7)(x - 12)}{(x + 1)(x)(x - 12)}

Step-by-step explanation:

A rational function is

\frac{p(x)}{q(x)}

where q(x) doesn't equal zero.

If p is a asymptote, or hole at that value, then we will use

(x - p)

Step 1: We have asymptote as 0 and -1 so our denomiator will include

(x - 0)(x - ( - 1)

Which is

(x)(x + 1)

So our denomator so far is

\frac{p(x)}{x(x + 1)}

Step 2: Find Holes.

Since 12 is the value of the hole,

(x - 12)

is a the binomial.

This will be both on the numerator and denomator so qe have

\frac{(x - 12)}{x(x + 1)(x - 12)}

Step 3: Put the x intercepts in the numerator.

Since 5 and -7 is the intercepts,

\frac{(x - 12)(x - 5)(x + 7)}{x(x + 1)(x - 12)}

Step 4: Horinzontal Asymptotes,

Multiply the numerator and denomiator out fully,

\frac{  {x}^{3} - 10 {x}^{2}  - 59x + 420 }{ {x}^{3} - 12 {x}^{2}   + x - 12}

Take a L

look at the coefficients,

Notice they have the same degree,3, this means if we divide the leading coefficents, we will get our horinzonral asymptote.

Multiply the numerator by 4.

\frac{4(x - 12)(x - 5)(x - 7)}{x(x + 1)(x - 12)}

Above is the function,

You might be interested in
How do i solve this
natima [27]

I think you are suppose to get "k" by itself, so you first multiply 2/5 to (k - 2)

-8 ≤ 2/5 (k - 2)

-8 ≤ 2/5k - 4/5

Next you add 4/5 on both sides

-8 + 4/5 ≤ 2/5k

Then you make the denominators the same in order to add them

-40/5 + 4/5 ≤ 2/5k

-36/5 ≤ 2/5k

Finally you multiply each side by 5/2 to get "k" by itself

-18 ≤ k

6 0
3 years ago
How do I even start this? And how to i order the equation to solve
Kobotan [32]

f(g(h(x)))=f(g(\sqrt x))=f(\sqrt x-1)=\boxed{(\sqrt x-1)^4+4}

This is because

h(x)=\sqrt x

g(x)=x-1

\implies g(h(x))=\sqrt x-1

(that is, replace any instance of <em>x</em> in the definition of <em>g</em> with √<em>x</em> )

and

f(x)=x^4+4

\implies f(\sqrt x-1)=(\sqrt x-1)^4+4

(replace any <em>x</em> in <em>f</em> with √<em>x</em> - 1)

Also acceptable:

(\sqrt x-1)^4+4=((\sqrt x)^4-4(\sqrt x)^3+6(\sqrt x)^2-4\sqrt x+1)+4

=\boxed{x^2-4x\sqrt x+6x-4\sqrt x+5}

(assuming <em>x</em> is not negative)

6 0
3 years ago
It’s not b!!!! Help me please
forsale [732]

Answer:

D maybe? im not sure

Step-by-step explanation:

3 0
3 years ago
|3k-2|=2|k+2| how do I do this when the 2 is on the other side??
grin007 [14]
|3k-2|=2|k+2l
Do Distributive Property and take 2 times by everything in the parenthesis. That will leave you with |3k-2|=2k+4. Then add like terms. 3k+2k=5k. Then -2+4=2. So you end up with 5k+2. I believe I'm right. If not please tell me.
3 0
3 years ago
2
pav-90 [236]

Answer:

I think A=66.67?Not too sure,sorry if I am wrong

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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