The answer is B.
(the equation to solve this with is: a^2 + b^2 = c^2)
What type of question is this
Answer:
Step-by-step explanation:
Prove: That the sum of the squares of 4 consecutive integers is an even integer.
An integer is a any directed number that has no decimal part or indivisible fractional part. Examples are: 4, 100, 0, -20,-100 etc.
Selecting 4 consecutive positive integers: 5, 6, 7, 8. Then;
= 25
= 36
= 49
= 64
The sum of the squares = 25 + 36 + 49 + 64
= 174
Also,
Selecting 4 consecutive negative integers: -10, -11, -12, -13. Then;
= 100
= 121
= 144
= 169
The sum of the squares = 100 + 121 + 144 + 169
= 534
Therefore, the sum of the squares of 4 consecutive integers is an even integer.
i tried ;w;
Step-by-step explanation:
m(−11+m)=0
Step 1: Simplify both sides of the equation.
m2−11m=0
Step 2: Factor left side of equation.
m(m−11)=0
Step 3: Set factors equal to 0.
m=0 or m−11=0
m=0 or m=11
Answer:
m=0 or m=11
The answer would be 1.40. The 3 significant figure are 1.39 and it wants us to round so we look at the 8 in 1.3981 and since 8 > 5 we know to round up.