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Salsk061 [2.6K]
2 years ago
15

Which equation represents the relationship shown in the graph above?

Mathematics
1 answer:
AURORKA [14]2 years ago
4 0

Answer:

y=2/3x+4

Step-by-step explanation:

y-intercept is 4

rise 2

run 3

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Slope is 7/3 and y intercept is -3.
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An open metal tank of square base has a volume of 123 m^3
snow_lady [41]

Answer:

  a) h = 123/x^2

  b) S = x^2 +492/x

  c) x ≈ 6.27

  d) S'' = 6; area is a minimum (Y)

  e) Amin ≈ 117.78 m²

Step-by-step explanation:

a) The volume is given by ...

  V = Bh

where B is the area of the base, x^2, and h is the height. Filling in the given volume, and solving for the height, we get:

  123 = x^2·h

  h = 123/x^2

__

b) The surface area is the sum of the area of the base (x^2) and the lateral area, which is the product of the height and the perimeter of the base.

S=x^2+Ph=x^2+(4x)\dfrac{123}{x^2}\\\\S=x^2+\dfrac{492}{x}

__

c) The derivative of the area with respect to x is ...

S'=2x-\dfrac{492}{x^2}

When this is zero, area is at an extreme.

0=2x -\dfrac{492}{x^2}\\\\0=x^3-246\\\\x=\sqrt[3]{246}\approx 6.26583

__

d) The second derivative is ...

S''=2+\dfrac{2\cdot 492}{x^3}=2+\dfrac{2\cdot 492}{246}=6

This is positive, so the value of x found represents a minimum of the area function.

__

e) The minimum area is ...

S=x^2+\dfrac{2\cdot 246}{x}=(246^{\frac{1}{3}})^2+2\dfrac{246}{246^{\frac{1}{3}}}=3\cdot 246^{\frac{2}{3}}\approx 117.78

The minimum area of metal used is about 117.78 m².

3 0
3 years ago
I need to know if this H(3,2),J(4,1),K(-2,-4),M(-1,-5) is parallel perpendicular or neither I need to show my work and write my
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Answer:

Step-by-step explanation:

H(3,2)  & J(4, 1)

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K(-2,-4)  & M(-1 , -5)

Slope =\dfrac{-5-[-4]}{-1-[-2]}\\\\=\dfrac{-5+4}{-1+2}\\\\= \dfrac{-1}{1}\\\\\\= -1

Line HJ and KM have same slopes. So, they are parallel

6 0
3 years ago
62 ÷ 34 = what is it
Irina18 [472]

Answer:

1.82352941176

Step-by-step explanation:

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