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Jobisdone [24]
3 years ago
5

IM DONE WITH THIS STUPID THING 50 POINTS TO THE PERSON WHO GETS IT ALL CORRECT.

Mathematics
1 answer:
soldi70 [24.7K]3 years ago
3 0
I underlined the numbers you needed
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What is the focus of the parabola? <img src="https://tex.z-dn.net/?f=y%3D%20%5Cfrac%7B1%7D%7B4%7D%20x%5E%7B2%7D%20-x%2B3" id="Te
OlgaM077 [116]
We know that
the equation of the parabola is of the form
y=ax²+bx+c
in this problem
y=1/4x²−x+3
where
a=1/4
b=-1
c=3
 the coordinates of the focus are
(-b/2a,(1-D)/4a)
where D is the discriminant b²-4ac
D=(-1)²-4*(1/4)*3-----> D=1-3---> D=-2
therefore
x coordinate of the focus
-b/2a----> 1/[2*(-1/4)]----> 2

y coordinate of the focus
(1-D)/4a------> (1+2)/(4/4)---> 3

the coordinates of the focus are (2,3)
3 0
2 years ago
Read 2 more answers
75 is what percent of 60
VLD [36.1K]
75 is 125% of 60. Hope this helps! :)
7 0
3 years ago
Here are two rectangles.
creativ13 [48]

Answer:

\frac{Area \:of\: rectangle\: A}{Area \:of\: rectangle\: B} =\frac{4}{3}

Step-by-step explanation:

Let the length of rectangle A be x units.

So, length of rectangle B

= x + 25% of x

= x + 0.25x

= 1.25x

Let the width of rectangle A be y units

So, Width of rectangle B

= \frac{3}{5}\times x\\=0.6x

Area of rectangle A = xy

Area of rectangle B

= 1.25x * 0.6y

= 0.75xy

\frac{Area \:of\: rectangle\: A}{Area \:of\: rectangle\: B} =\frac{xy}{0.75xy}\\\\\frac{Area \:of\: rectangle\: A}{Area \:of\: rectangle\: B} =\frac{1}{0.75}\\\\\frac{Area \:of\: rectangle\: A}{Area \:of\: rectangle\: B} =\frac{100}{75}\\\\\red{\bold{\frac{Area \:of\: rectangle\: A}{Area \:of\: rectangle\: B} =\frac{4}{3}}} \\\\

8 0
2 years ago
The _______ of any statistical test represents the probability that the results were obtained by chance alone.
Levart [38]
ρ-Value, Probability Value, or <span>Observed Level of Significance
is the definition of </span><span>any statistical test represents the probability that the results were obtained by chance alone.</span>
6 0
2 years ago
What binomial do you have to add to the polynomial:
marshall27 [118]

Answer:

a)  -2x^2+5xy

b)  -3y^2+5xy

Step-by-step explanation:

<u>Part (a)</u>

Given polynomial  :2x^2+3y^2-5xy+1

The binomial that should be added to the given polynomial to get a polynomial that does not contain the variable x is:

-2x^2+5xy

(2x^2+3y^2-5xy+1)+(-2x^2+5xy)

=2x^2+3y^2-5xy+1-2x^2+5xy

=2x^2-2x^2+3y^2-5xy+5xy+1

=3y^2+1

<u>Part (b)</u>

Given polynomial  :2x^2+3y^2-5xy+1

The binomial that should be added to the given polynomial to get a polynomial that does not contain the variable y is:

-3y^2+5xy

(2x^2+3y^2-5xy+1)+(-3y^2+5xy)

=2x^2+3y^2-5xy+1-3y^2+5xy

=2x^2+3y^2-3y^2-5xy+5xy+1

=2x^2+1

7 0
2 years ago
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