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3 years ago

IM DONE WITH THIS STUPID THING 50 POINTS TO THE PERSON WHO GETS IT ALL CORRECT.

Mathematics

1 answer:

soldi70 [24.7K]3 years ago

3 0

I underlined the numbers you needed

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. Given ABCD 2 EFGH, what is the value of X? H Н 6 m 7 m 5 m А D 9 m

Nookie1986 [14]

Answer:

x=6 cm

Step-by-step explanation:

As given in the question that ABCD is congruent to EFGH.

We can say that,

AD <-----> EH {Corresponding Parts Of Congruent Polygons}

AD=EH

We are given that,

$AD=9\\EH=(2x-3)\\Hence,\\As\ AD=EH\\9=2x-3\\9+3=2x\\12=2x\\x=6$

5 0

3 years ago

Can someone please help

Dmitrij [34]

Answer:

1) a. 15ft

b. 6ft

c. 30ft

2) a. 16m

b. 12m

c. 192m

8 0

3 years ago

Read 2 more answers

Find the horizontal asymptote

eimsori [14]

Answer:

Correct answer: h = 3/5 or y = 3/5

Step-by-step explanation:

Given:

h(x) = (3x² - 9x - 4) / (5x² - 4x + 8)

h = lim x -> ∞ (3x² - 9x - 4) / (5x² - 4x + 8) the numerator and denominator will be divided by x² and get

h = lim x -> ∞ (3 - 9(1/x) - 4 (1/x²)) / (5 - 4(1/x) + 8 (1/x²)

The terms 1/x and 1/x² when x strives ∞ they strives 0

x -> ∞ ⇒ 1/x -> 0 and x -> ∞ ⇒ 1/x² -> 0

h = (3 - 0 - 0) / (5 - 0 + 0)

Horizontal asymptote is h = 3/5 or y = 3/5

God is with you!!!

5 0

4 years ago

A sweater is marked down from $25 to $18. What is the percent of change

zhenek [66]

Answer:

28 percent off is the answer :)

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

(sin x)(tan x cos x - cot x cos x) = 1 - 2 cos2x

Aliun [14]

As

$\tan x=\dfrac{\sin x}{\cos x}$
$\cot x=\dfrac{\cos x}{\sin x}$

we have

$\sin x(\tan x\cos x-\cot x\cos x)=\sin x\left(\sin x-\dfrac{\cos^2x}{\sin x}\right)=\sin^2x-\cos^2x$

Recalling that $\cos2x=\cos^2x-\sin^2x$ , we end up with

$-\cos2x=1-2\cos2x$
$1=\cos2x$
$\implies2x=2n\pi$

(where $n$ is any integer)

$\implies x=n\pi$

5 0

3 years ago