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zalisa [80]
2 years ago
9

Lab report calorimetry and specific heat HELP PLZ

Chemistry
1 answer:
dolphi86 [110]2 years ago
8 0

Explanation:

Specific heat capacity can be calculated using the following equation: q = mc∆T In the equation q represents the amount of heat energy gained or lost (in joules ), m is the mass of the substance (in grams), c is the specific heat capacity of the substance (in J/g °C), and ∆T is the temperature change of the substance 

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I believe the correct answer is option B. Molarity is the <span>number of moles of solute that is dissolved in 1 liter of solution. It is another way of expressing concentration of a mixture especially for solutions. Percent by mass is grams solute per grams of solution. Percent by volume is liter solute per liter per solution.</span>
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3 years ago
The scientific notation 2 x 10-2 has what value? <br> 0.02<br> 0.002<br> 0.2<br> 0.0002
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Answer:

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2 years ago
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A 50.0 mL sample of a 1.00 M solution of CuSO4 is mixed with 50.0 mL of 2.00 M KOH in a calorimeter. The temperature of both sol
Scorpion4ik [409]

Answer:

see explanation

Explanation:

Step 1: Data given

Volume of 1M CusO4 = 50.0 mL = 0.05 L

Volume of 2M KOH = 50.0 mL = 0.05 L

Temperature before mixing= 17.8 °C

Temperature after mixing = 32.4 °C

The heat capacity of the calorimeter is 12.1 J/K

Step 2: The balanced equation

CuSO4(aq)+ 2KOH(aq) →Cu(OH)2(s) + K2SO4(aq)

Step 3: Calculate mass of the solution

Suppose the density of the solution is 1 g/mL

Total volume = 100 mL

Mass of the solution = density * volume

Mass of the solution = 1g/mL * 100 mL = 100 grams

Step 4:

Q = m*c*ΔT

with m = the mass of the solution = 100 grams

with c= the heat capacity of the solution = 4.184 J/g°C

with ΔT = 32.4 - 17. 8 = 14.6 °C

Q = 6108.64 J

Step 5: Calculate the energy of the calorimeter

Q = c*ΔT

Q = 12.1 J/K * 14.6

Q = 176.66 J

Step 6: Calculate total heat

Qtotal = 6108.64 + 176.66 = 6285.3 J = 6.29 kJ (negative because it's exothermic)

Step 7: Calculate moles

Moles CuSO4 = 0.05 L * 1M = 0.05 moles

Moles KOH = 0.05 L * 2M = 0.10 moles

ΔH = -6.29 kJ / 0.05 moles = -125.8 kJ/mol

3 0
3 years ago
Calculate mole fraction of benzene (70 g) having 30 gram of mass of carbon tetrahedral​
Fynjy0 [20]

Moles of benzene

  • 70/90=7/9=0.8mol

moles of CCl_4

  • 30/154
  • 0.2mol

Now

\\ \rm\Rrightarrow \chi_{C_6H_6}

\\ \rm\Rrightarrow \dfrac{\chi_{C_6H_6}}{\chi_{sol^n}}

\\ \rm\Rrightarrow \dfrac{0.8}{0.8+0.2}

\\ \rm\Rrightarrow \dfrac{0.8}{1}

\\ \rm\Rrightarrow 0.8

4 0
2 years ago
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