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klemol [59]
3 years ago
13

Help please, will mark you as brainliest

Chemistry
1 answer:
Veseljchak [2.6K]3 years ago
5 0

Answer:

what does it say under the paragraph

Explanation:

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The maximum amount of nickel(II) cyanide that will dissolve in a 0.220 M nickel(II) nitrate solution is...?
sweet [91]

Answer : The maximum amount of nickel(II) cyanide is 5.84\times 10^{-12}M

Explanation :

The solubility equilibrium reaction will be:

                       Ni(CN)_2\rightleftharpoons Ni^{2+}+2CN^-

Initial conc.                        0.220       0

At eqm.                             (0.220+s)   2s

The expression for solubility constant for this reaction will be,

K_{sp}=[Ni^{2+}][CN^-]^2

Now put all the given values in this expression, we get:

3.0\times 10^{-23}=(0.220+s)\times (2s)^2

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Therefore, the maximum amount of nickel(II) cyanide is 5.84\times 10^{-12}M

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