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Mumz [18]
3 years ago
15

A hypothesis is made at:

Chemistry
2 answers:
AlekseyPX3 years ago
7 0
C is the right answer hope this is right

kicyunya [14]3 years ago
6 0
It is obviously a “C” answer that outlines the question given.
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What is the volume of the rectangular prism below? A.38,832 mm3 B.480,000 mm3 C.499,200 mm3 D.501,120 mm3
Mkey [24]

Answer:

c.

Explanation:

8 0
3 years ago
Use the Gizmo to estimate the age of each of the objects below. For these questions, each second in the Gizmo represents 1,000 y
ziro4ka [17]

Answer:

Check the explanation

Explanation:

AT = A0 e(-T/H)

... where A0 is the starting activity, AT is the activity at some time T, and H is the half-life, in units of T.

Substituting what we know, we get...

0.71 = (1) e(-T/5730)

Solve for T...

loge(0.71) = -T/5730

T = -loge(0.71)(5730)

T = 1962 (conservatively rounded, T = 2000)

similarly for all

for aboriginal charcoal

0.28 = (1) e(-T/5730)

Solve for T...

loge(0.28) = -T/5730

T = -loge(0.28)(5730)

T = 7294 (conservatively rounded, T = 7000)

for mayan headdress

0.89 = (1) e(-T/5730)

Solve for T...

loge(0.89) = -T/5730

T = -loge(0.89)(5730)

T = 667 (conservatively rounded, T = 700)

for neanderthal

0.05 = (1) e(-T/5730)

Solve for T...

loge(0.05) = -T/5730

T = -loge(0.05)(5730)

T = 17165 (conservatively rounded, T = 17000)

7 0
3 years ago
How do elements on the right side of the periodic table differ from elements on the left side of the table?
lozanna [386]

The answer is c.


Elements on the left side of the table are metals, such as sodium, lithium, potassium, etc.


Elements on the right side are non metals, such as Chlorine, Fluorine, Bromine, etc.

4 0
3 years ago
A few pieces of dry ice, CO2(s), at -78°C are placed in a flask that contains air at 21°C. The flask is sealed by placing an uni
arsen [322]
The direction of heat flow is from surroundings to system (air to ice), the dry ice is subliminating.
8 0
4 years ago
Read 2 more answers
A standard 10.00 g mass is weighed on an analytical balance 100 times. The average and standard deviation obtained gives 10.12 ±
Mekhanik [1.2K]

Answer:

There was an improvement in accuracy. There was no change in precision.

Explanation:

<em>The average mass after recalibration is closer to the mass of the standard, </em>so the recalibration improved the accuracy<em> </em>(the measurement is closer to an accepted 'true' value).

The standard deviation did not change, so the precision (or how disperse the measurements are) was not affected.

5 0
3 years ago
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