S + O2 → SO2
Moles of S:
11/32.06 = 0.3431 mol
Moles of O2:
44/15.999 = 2.75 mol
Sulfur will be the limiting reagent.
Oxygen will be the excess reagent
2.75 - 0.3431 = 2.4071 mols of oxygen leftover
2.4071 * 15.999 = 38.511
38.511 grams of oxygen will be leftover
Answer:
0.506 g
Explanation:
we know that one miligram is equal to 0.001 g or we can say that one gram contain thousand miligram. so,
if the mass of drug is 506 mg then to convert it into gram we have to divide 506 mg into 1000.
The answer to this question would be: <span>NaOH solution
Limiting reagent is the reagent that totally consumed in the reaction. To answer this question you need to know the equation for the chemical reaction. The equation would be:
</span><span>HCl + NAOH = H2O + NACl
</span>
All of the coefficient in the reaction is 1, which mean 1 HCl will react to 1 NaOH. In this question, the concentration of HCl and NaOH is same so the amount of the molecule can be reflected by the volume. NaOH has lower volume compared to HCl so it is clear that NaOH will be totally consumed in this reaction.
Answer:
14.91 mL
Explanation:
<em>Assuming the weak acid is monoprotic</em>, we can solve this problem using the equation:
Where subscript 1 stands for the Volume and Concentration of the weak acid, while 2 stands for those of NaOH.
We <u>input the data</u>:
- 25.00 mL * 0.1084 M = 0.1817 M * V₂
And solve for V₂:
