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mash [69]
3 years ago
14

Please help im so bad at this :(

Mathematics
2 answers:
Andrew [12]3 years ago
7 0
27/125 sorry if I’m wrong
NemiM [27]3 years ago
4 0

Answer:

27/125

Step-by-step explanation:

multiply it 3 times

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Pls answer and show WORK pls do it right
adelina 88 [10]

Answer:

4/6

Step-by-step explanation:

1/2 needs to be converted to sixths, so we would multiple the numerator and the denominator by 3, because 2 goes into 6, 3 times, then we would get 3/6 + 1/6, then just add, 1 + 3 = 4, and then you end up with 4/6. Have A Great Day!

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3 years ago
What is the slope-intercept equation for this line?
miskamm [114]

Answer:

the slope intersection is xy

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If you add the year of my birth to this year, subtract the year of my 20th birthday and the year of my 85th birthday, and then a
Bas_tet [7]
It's not possible for the result to be 49
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3 years ago
A consumer products company found that 44​% of successful products also received favorable results from test market​ research, w
Korolek [52]

Answer:

  1. 0.80
  2. 0.289
  3. 0.20
  4. 0.711

Step-by-step explanation:

Given:

P(S\cap F)=0.44\\P(S\cap F^{c})=0.13\\P(S^{c}\cap F^{c}) = 0.32\\P(S^{c}\cap F) = 0.11

The rule of total probability states that:

P(A) = P(A\cap B) + P(A\cap B^{c})

Compute the individual probabilities as follows:

P(S) = P(S\cap F) + P(S\cap F^{c})\\=0.44+0.13\\0.57

P(S^{c}) = 1 - P(S)\\=1-0.57\\=0.43

P(F) = P(S\cap F) + P(S^{c}\cap F)\\=0.44+0.11\\=0.55

P(F^{c})=1-P(F)\\=1-0.55\\=0.45

Conditional probability of an event A given B is:

P(A|B)=\frac{P(A\cap B)}{P(B)}

  • Compute the value of P(S|F):

         P(S|F)=\frac{P(S\cap F)}{P(F)}\\=\frac{0.44}{0.55}\\=0.80

  • Compute the value of P(S|F^{c})

        P(S|F^{c})=\frac{P(S\cap F^{c})}{P(F^{c})}\\=\frac{0.13}{0.45}\\=0.289

  • Compute the value of P(S^{c}|F)

        P(S^{c}|F)=\frac{P(S^{c}\cap F)}{P(F}\\=\frac{0.11}{0.55}\\=0.20

  • Compute the value ofP(S^{c}|F^{c})

       P(S^{c}|F^{c})=\frac{P(S^{c}\cap F^{c})}{P(F^{c})}\\=\frac{0.32}{0.45}\\=0.711

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3 years ago
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