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2 years ago

Please help im so bad at this :(

Mathematics

2 answers:

Andrew [12]2 years ago

7 0

27/125 sorry if I’m wrong

NemiM [27]2 years ago

4 0

Answer:

27/125

Step-by-step explanation:

multiply it 3 times

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Name 4 pairs of corresponding angles

SOVA2 [1]

Answer:

1. Alternate angles, 2. Right angle, 3. Acute Angle, 4. Reflex angle

Step-by-step explanation:

5 0

2 years ago

Consider the case of a triangle with sides 5, 12, and the angle between them 90°.

Daniel [21]

Answer:

a) Applying Pithagoras Theorem

b) Trigonometric relations

c) No we can not

d) No we can not

e) See step-by-step explanation

f) See step-by-step-explanation

Step-by-step explanation:

a) The easiest method for calculating the missing side is applying Pithagoras Theorem

c² = a² + b²

c² = (5)² + (12)² ⇒ c² = 25 + 144 ⇒ c² = 169 ⇒ c = 13

b) The easiest method to find the missing angles, is to calculate the sin∠ and then look for arcsin fuction in tables.

sin ∠α = 5/13 sin ∠α = 0.3846 ⇒ arcsin (0.3846 ) α = 23⁰

Now we can either get the other angle subtracting 180 - 90 - 23 = 67⁰

Or calculating sinβ = 12 /13 sinβ = 0.9230 arcsin(0.9230) β = 67⁰

c) The law of cosines should not be applied to right triangles, in fact for instance in our particular case we have:

Question a)

c² = a² + b² - 2*a*b*cos90⁰ (law of cosines ) but cos 90⁰ = 0

then c² = a² + b² which is the expression for theorem of Pithagoras

In case you look for calculating the missing angles

c² = a² + b² - 2*5*13*cos α

169 = 25 + 144 - 2*5*13* cos α

As you can see 169 - 25 - 144 = 0

Then we can not apply law of cosine in right triangles, we shoul apply trigonometric relations and Pithagoras theorem, and as we saw you can get the expression of Pithagoras theorem from cosine law

c² = a² + b² - 2*a*b*cos∠90° cos ∠ 90° = 0

Then c² = a² + b²

3 0

2 years ago

Please help me with this question thanks

IceJOKER [234]

The diffrence of 37 and B.

3 0

2 years ago

Read 2 more answers

Points a and b lie on a circle with radius 1, and arc ab has length π 3 . what fraction of the circumference of the circle is th

OleMash [197]

The circumference of the circle is equal to

C = 2πr, where r is the radius of the circle.
Substituting r = 1, the circumference is equal to
C = 2π

Since the arc ab is π/3, its fraction of the circumference is equal to

Fraction = π/3 ÷ 2π
Fraction = 1/6

4 0

3 years ago

Suppose Mrs. Reyes would like to save Php 1,000.00 at the end of each month for 9 months in a fund that gives 5% per annum compo

scoray [572]

The rate is r = 5% = 0.05
Compounding interval, n = 12, monthly compounding
Therefore
r/n = 0.05/12 = 0.004167

The first deposit has a duration of 7 months. Its value is
a₁ = 1000*(1.004167)⁷

The second deposit has a duration of 6 months. Its value is
a₂ = 1000*(1.004167)⁶
and so on.

The values after each month from a geometric sequence with
a = 1000*(1.004167)
r = 1.004167

Over 7 months, the total sum is
$\frac{1000*1.004167*(1-1.004167^{7} )}{1-1.004167} =7117.64$

Answer: Php 7,117.64

5 0

3 years ago