All categories

3 years ago

Help me plsssssssss:(

Mathematics

1 answer:

weqwewe [10]3 years ago

6 0

Answer:

1: $1200

2: Food ($6000)

3: $3000

4: $1800

5: $3000

Step-by-step explanation:

1: 10%*12000 = 1200

2: Food 50%*12000 = 6000

3: 25%*12000 = 3000

4: 15%*12000 = 1800

5: Food - Education = 6000 - 3000 = 3000

You might be interested in

ASAP i need this TODAY PLEASE)For a survey, students in a class answered these questions: Do you play a sport? Do you play a mus

kondaur [170]

To the nearest percentage point, what percentage of students who play a sport don’t play a musical instrument?

First, using the information given, fill out the chart with the rest of the data (in the image attached)

Then find the number of students who play a sport and don’t play a musical instrument, which in the chart is 11

Place 11 over the total: $\frac{11}{25}$ and convert to a percentage:

44%

5 0

3 years ago

A container holds 5L of fluid. Does it hold more than or less than 500mL of fluid

Yuri [45]

There are 1000 mL in one liter, so there are 5000 Ml in the 5 L container. thus, it holds more than the 500 mL container.

7 0

4 years ago

How does the graph of y = 3–x compare to the graph of

DerKrebs [107]

Answer: the line is no longer linear

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Melania walked her dog 2 1/5 miles. Cathy walked her dog 1 3/4 times as far as Melania did. How many miles did Cathy walk her do

Step2247 [10]

Make the fractions improper to multiply.2 1/5 becomes 11/5 and 1 3/4 becomes 7/4. multiply the numerators then multiply the denominators. you get 77/20, which is simplest form. don't let teachers feed you that bs about it having to be a mixed number. an improper fraction is way more useful.

5 0

3 years ago

A random variable x follows a normal distribution with mean d and standard deviation o=2. It is known that x is less than 5 abou

Vaselesa [24]

Answer:

The mean of this distribution is approximately 3.96.

Step-by-step explanation:

Here's how to solve this problem using a normal distribution table.

Let $z$ be the

$\displaystyle z = \frac{x - \mu}{\sigma}$ .

In this question, $x = 5$ and $\sigma = 2$ . The equation becomes

$\displaystyle z = \frac{5 - \mu}{2}$ .

To solve for $\mu$ , the mean of this distribution, the only thing that needs to be found is the value of $z$ . Since

The problem stated that $P(X \le 5) = 69.85\% = 0.6985$ . Hence, $P(Z \le z) = 0.6985$ .

The problem is that the normal distribution tables list only the value of $P(0 \le Z \le z)$ for $z \ge 0$ . To estimate $z$ from $P(Z \le z) = 0.6985$ , it would be necessary to find the appropriate

Since $P(Z \le z) = 0.6985$ and is greater than $P(Z \le 0) = 0.50$ , $z > 0$ . As a result, $P(Z \le z)$ can be written as the sum of $P(Z < 0)$ and $P(0 \le Z \le z)$ . Besides, $P(Z < 0) = P(Z \le 0) = 0.50$ . As a result: