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amid [387]
3 years ago
7

Plzzzzzzzzzzzzzzzzzz help meeeeee

Chemistry
2 answers:
natka813 [3]3 years ago
5 0
Plzzzzzzzzzzzzzzzz help meeeeeeee
ratelena [41]3 years ago
4 0
It is a because I know it is
You might be interested in
Question 1 (1 point)
andrezito [222]

Answer:

  1. <u>True</u><u> </u>
  2. <u>B</u><u>.</u><u> </u><u>24</u><u> </u><u>hours</u><u> </u>
  3. <u>Light</u><u> </u><u>and</u><u> </u><u>Dark</u><u> </u>
  4. <u>A</u><u>.</u><u> </u><u>To</u><u> </u><u>spin</u><u> </u><u>on</u><u> </u><u>an</u><u> </u><u>Axis</u><u> </u>
  5. <u>True</u><u> </u>
  6. <u>Nearest</u><u> </u><u>P0INTS</u><u> </u>
  7. <u>B</u><u>.</u><u> </u><u>365</u><u> </u><u>days</u><u> </u>
  8. <u>True</u><u> </u>
  9. <u>A</u><u>.</u><u> </u><u>January</u><u> </u>
  10. <u>B</u><u>.</u><u> </u><u>July</u><u> </u>
  11. <u>Summer</u><u> </u>
  12. <u>B</u><u>.</u><u> </u><u>T</u><u>he tilt of the Earth on its axis</u>
  13. <u>True</u><u> </u>
  14. <u>¿</u><u>-</u><u>¿</u>
  15. <u>¿</u><u>-</u><u>¿</u>
  16. <u>B</u><u>.</u><u> </u><u>June</u>
  17. <u>A</u><u>.</u><u> </u><u>September</u><u> </u>
  18. <u>B</u><u>.</u><u> </u><u>December</u><u> </u><u>and</u><u> </u><u>March</u><u> </u>

Explanation:

Sorry yan lang alm but I hope it helps

<h2><u>#CARRYONLEARNING</u><u> </u></h2><h2><u>#STUDYWELL</u><u> </u></h2>
5 0
3 years ago
A vessel with a volume of 32. 5 l contains 2. 80 g of n2 gas, 0. 403 g of h2 gas, and 79. 9 g of ar gas. at 25°c, what is the to
d1i1m1o1n [39]

The total pressure of the gases in the vessel is found out by using the partial pressures of individual gases and adding them up. The total pressure of the gases in the vessel is 1.72 atm.

The Partial pressure of the gases is the individual pressure of the gases present in a vessel containing a mixture of gases. The total pressure can be found out by adding partial pressure of all gases.

Given:

Volume of vessel, V= 32.5L

Mass of Nitrogen gas = 2.8g

Mass of Hydrogen gas = 0.403g

Mass of Argon gas = 79.9g

We know that:

             Molar Mass of Nitrogen gas = 28g

             Molar Mass of Hydrogen gas = 2g

             Molar Mass of Argon gas = 40g

∴ Moles of gas = Given mass / Molar mass

∴ Using the Ideal Gas Equation:

PV = nRT

where, P is the Pressure of gas

V is the volume of gas

n is the moles of gas

R is the Universal Gas constant

T is the temperature

Applying the above equation of all three gases indivudually,

∴ For Nitrogen,

P₁V = n₁RT                    

⇒ P₁ × 32.5 = 2.8/28 × 0.082 × 298

⇒ P₁ = 0.07atm

∴ For Hydrogen,

P₂V = n₂RT                    

⇒ P₂ × 32.5 = 0.4/2 × 0.082 × 298

⇒ P₂ = 0.15 atm

∴ For Argon,

P₃V = n₃RT                    

⇒ P₃ × 32.5 = 79.9/40 × 0.082 × 298

⇒ P₃ = 1.5 atm

∴ Total pressure of vessel, P = P₁ + P₂ + P₃

                                         P = 1.72 atm

The total pressure of the gases in the vessel is 1.72 atm.

Learn more about Partial pressure here, brainly.com/question/23841760

#SPJ4

6 0
1 year ago
An unknown compound was found to have a percent composition as follows: 47.0%, 14.5 carbon, and 38.5 oxygen. What is its empiric
shusha [124]

 KCO₂

 K₂C₂O₄

Explanation:

Given parameters:

Percent composition:

             K = 47%

             C = 14.5%

             O = 38.5%

Molar mass of compound = 166.22g/mol

Unknown:

Empirical formula of compound = ?

Molecular formula of compound = ?

Solution:

The empirical formula of a compound is its simplest formula. Here is how to solve for it:

 

                                K                                C                           O

Percent

composition           47                               14.5                       38.5

Molar mass            39                                  12                           16

Number

of moles               47/39                         14.5/12                     38.5/16

moles                    1.205                          1.208                          2.4

Dividing

by smallest      1.205/1.205               1.208/1.205                      2.4/1.205

                                1                                  1                                        2

Empirical formula               KCO₂

Molecular formula

  This is the actual combination of the atoms:

          Molecular formula =   ( empirical formula of KCO₂)ₙ

 Molar mass of empirical formula = 39 + 12 + 2(16) = 83g/mol

      n factor = \frac{true molecular mass}{molar mas of empirical formula}

      n factor = \frac{166.22}{83} =  2

Molecular formula of compound = ( KCO₂)₂ = K₂C₂O₄

Learn more:

Empirical formula brainly.com/question/2790794

#learnwithBrainly

6 0
4 years ago
Why should scientists study the effects of chemicals on the environment?
Damm [24]
The answer should be C makes very snesen
5 0
3 years ago
Molecules that are similar enough to a neurotransmitter to bind to its receptor sites on a dendrite and block that neurotransmit
nataly862011 [7]
Molecules that are similar enough to a neurotransmitter to bind to its receptor sites on a dendrite and block that neurotransmitter's effects are called <span>antagonists.</span>
6 0
3 years ago
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