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FrozenT [24]
3 years ago
13

Whichof the following is another name for science

Chemistry
1 answer:
snow_lady [41]3 years ago
8 0
Field or discipline
 hope it helped
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Vaporization is an endothermic process. Using the terms 'kinetic energy' and 'intermolecular forces', explain how the addition o
Novay_Z [31]
An endothermic process is a process that needs energy in order to proceed. This is the opposite of exothermic which is a process of releasing energy. During an endothermic process, the temperature of the system is increased thus exciting the molecules and allowing them to move faster. This will cause liquid to vaporize. 
5 0
4 years ago
Calculate the morality for the following<br> 10.5 kg of Na2 SO4. 10H2O in 18.60 L
Serggg [28]

Answer:

1.75M

Explanation:

The problem deals with finding the molarity of the given compound.

 The compound is:

             Na₂SO₄.10H₂O

Mass of the compound  = 10.5kg  = 10500g

Volume of the compound  = 18.6L

Molarity is the number of moles of solute in a solution;

     Molarity  = \frac{number of moles }{volume}  

 Number of moles  = \frac{mass}{molar mass}  

 Molar mass of   Na₂SO₄.10H₂O  = 2(23) + 32 + 4(16) + 10[2(1) + 16]

                                                       = 322g/mol

 Now;

    Number of moles  = \frac{10500}{322}   = 32.6mole

So;

  Molarity  = \frac{32.6}{18.6}   = 1.75M

5 0
3 years ago
In order to prepare a 0.523 m aqueous solution of potassium iodide, how many grams of potassium iodide must be added to 2.00kg o
Lerok [7]
M = amount of the solute  / mass of the <span>solvent

0.523 = x / 2.00 

x = 0.523 * 2.00

x = 1,046  moles

molar mass KI = </span><span>166.0028 g/mol
</span><span>
Mass = 1,046 * 166.0028

Mass </span>≈<span> 173.63 g

hope this helps!

</span>
6 0
4 years ago
HELP!! The splitting of a(n) ________ to produce energy is called a fission reaction.
Zina [86]
The answer is B atom
8 0
3 years ago
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Which of the following bonds is polar?<br> a) F-F<br> b) O-H<br> c) O-O<br> d) H-H
SSSSS [86.1K]
D) H-H
Hope this helps.
6 0
3 years ago
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