The pitch of the sound of the car will appear to be <span>lower than the pitch of the car next to you</span>
Answer : The correct option is, (D) 278 K
Explanation :
We are given temperature
.
Now the conversion factor used for the temperature is,

where, K is kelvin and
is Celsius.
Now put the value of temperature, we get

Therefore, the temperature 278 K is equal to the 
Answer:
(a) 
(b) 
Explanation:
Given data
Distance r₁=50 m
Distance r₂=2 m
Intensity I₂=2.0 W/m²
To find
(a) The Sound Intensity I₁
(b) The Sound Intensity level β
Solution
For (a) the Sound Intensity I₁

For (b) the Sound Intensity level β
The Sound Intensity level β is calculated as follow

Answer:
1.68m/s^2
Explanation:
using V^2=U^2+2×a×s formula.
If,
(Final Velocity)V=45
(Initial Velocity)U=0 because it starts from rest
(Distance)S=600m
(acceleration)a= ?
now,
using formula,
45^2=0^2+2×a×600
2025= 1200a
a=2025÷1200
a = 1.68m/s^2(The unit of acceleration is m/s^2)
Therefore the acceleration is 1.68m/s^2
Hope it works !!!