Answer:
Explanation:
As we know that the block of wood is suspended by spring
Now at equilibrium position we have net force balanced on it
so we have
so we will have
now the time period of the spring block system for one complete oscillation is given as
now plug in all values in it
Now total time to complete 3 cycles is given as
V^2-u^2=2as
v=final velocity=unkown
u=initial velocity=0 m/s, because freely falling
a=acceleration due to gravity=9.8 m/s^2
s=distance (here height) traveled=4.5m
therefore the final velocity,
v^2=2*9.8*4.5
v=<span>9.39m/s</span>
Answer:
The answer to your question is Gamma Rays.
Explanation:
I'm sorry if I get this wrong, I also have this same question. But, I believe I am right!
Answer:
Diaplacement s=1.80km
Final velocity v=360km/h
It starts from rest. So, initial velocity u=0
We need to find the constant acceleration (a).
using the equation of motion v
2
=u
2
+2as
360
2
=0
2
+2×a×1.8
a=
3.6
360×360
a=36000km/h
2
<span>Ax=24 cos(15)=23.1822Ax=24 cos(15)=23.1822
Ay=â’24 sin(15)=â’6.2117Ay=â’24 sin(15)=â’6.2117
and
Bx=0Bx=0
By=8By=8
To find the distance b you want to find the vector that goes from A to 15 km E (vector C). Calling the differnce in A + B and C D, then we know
[math]D = (A + B) - C. So we have for D:
Dx=(Ax+Bx)â’Cx=â’1.8178Dx=(Ax+Bx)â’Cx=â’1.8178
Dy+(Ay+By)â’Cy=1.7883Dy+(Ay+By)â’Cy=1.7883
D=D2x+D2y‾‾‾‾‾‾‾‾âš=2.2567</span>