CAN SOMEONE PLEASE HELP ME PLEASE

Please don’t skip!!! I need help!!

horsena [70]

P = [60] cm

Explanation:

6.5 cm + 6.5 cm + 7.5 cm + 7.5 cm + 7.5 cm + 7.5 cm + 8.5 cm + 8.5 cm

7 0

3 years ago

What is the volume of a sphere that has a diameter of 12 cm? (Round to the nearest whole number)

ivann1987 [24]

Answer:

V≈904.78cm³

Step-by-step explanation:

3 0

3 years ago

Tyrone biked 45 miles at an average speed of 18 miles per hour, without stopping. About how long did the ride take him? Use the

Goshia [24]

Answer: 2 1/2 hours

Step-by-step explanation: 45/18 = 2 1/2

5 0

10 months ago

An airplane travels 600 miles against the wind in 4 hours, and makes the return trip with then same wind in 2 hours. Find the sp

SOVA2 [1]

Answer:

The speed of wind is 75 miles / hour

Step-by-step explanation:

Let's assume

speed of airplane is x miles /hour

speed of wind is y miles /hour

Against wind:

An airplane travels 600 miles against the wind in 4 hours

against wind means resultant speed will be less

so, speed =x-y

total distance traveled in 4 hour is

$=4(x-y)$

and this has to be equal to 600

$600=4(x-y)$

Divide both sides by 4

and we get

$x-y=150$

With wind:

makes the return trip with then same wind in 2 hours

with wind means resultant speed will be more

so, speed =x+y

total distance traveled in 2 hour is

$=2(x+y)$

and this has to be equal to 600

$600=2(x+y)$

Divide both sides by 2

and we get

$x+y=300$

So, we get system of equations

$x-y=150$

$x+y=300$

now, we can solve it by adding both equations

$x-y+x+y=150+300$

$2x=450$

now, we can solve for x

$x=225$

now, we can find y by plugging x into any one equation

$225+y=300$

$y=75$

So,

The speed of wind is 75 miles / hour

3 0

2 years ago

A regional automobile dealership sent out fliers to prospective customers indicating that they had already won one of three diff

igor_vitrenko [27]

Answer:

(a) 31101

(b) $5.65

(c) $113.38

Step-by-step explanation:

The complete question is:

A regional automobile dealership sent out fliers to prospective customers indicating that they had already won one of three different prizes: an automobile valued at $20,000, a $125 gas card, or a $5 shopping card. To claim his or her prize, a prospective print on the back of the flier listed the probabilities of winning. The chance of winning the car was 1 out of 31,101, the chance of winning the gas card was 1 out of 31,101, and the chance of winning the shopping card was 31, 099 out of 31,101.

Solution:

The information provided is as follows:

$P(\text{Car})=\frac{1}{31101}\\\\P(\text{Gas Card})=\frac{1}{31101}\\\\P(\text{Shopping Card})=\frac{31099}{31101}$

(a)

The number of fliers the automobile dealership sent out is, <em>n</em> = 31,101.

This is because the probability of winning any of the three prize is out of 31,101.

(b)

Compute the expected value of the prize won by a prospective customer receiving a flier as follows:

$E(X)=\sum x\times P(X=x)$

$=[20000\times \frac{1}{31101}]+[125\times \frac{1}{31101}]+[5\times \frac{31099}{31101}]\\\\=0.6431+0.0040+4.9997\\\\=5.6468\\\\\approx 5.65$

Thus, the expected value of the prize won by a prospective customer receiving a flier is $5.65.

(c)

Compute the standard deviation of the prize won by a prospective customer receiving a flier as follows:

$SD(X)=\sqrt{V(X)}=\sqrt{E(X^{2}-(E(X))^{2}}$

$=\sqrt{[(20000)^{2}\times \frac{1}{31101}+(125)^{2}\times \frac{1}{31101}+(5)^{2}\times \frac{31099}{31101}]-(5.65)^{2}}\\\\=\sqrt{12854.9011}\\\\=113.37947\\\\\approx 113.38$

Thus, the standard deviation of the prize won by a prospective customer receiving a flier is $113.38.

8 0

3 years ago