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Aliun [14]
3 years ago
12

Mike has a rowboat for crossing the river. The rowboat can hold only 200 pounds without sinking. If mike has his two little brot

hers with him, Jerry and David, who weigh 100 and 80 pounds respectively, and Mike weighs 160 pounds, how can all three boys get across the river?
This is not a Joke btw.
Mathematics
1 answer:
Elina [12.6K]3 years ago
4 0

Something that could be done is to tie a rope long enough to cross the river and send the two younger brothers across first, then have Mike pull the boat back across the river with the rope and him get in the boat and row it across the river with just himself and the gear.

Another option is you can unload some gear, put the boys in the boat, row them across the river, unload the two younger boys, go back for the rest of gear and load it into the boat then come back.


Hope this helps!

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Answer:

z=\frac{0.40 -0.45}{\sqrt{\frac{0.45(1-0.45)}{370}}}=-1.933  

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Information given

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\hat p=0.4 estimated proportion of  readers owned a laptop

p_o=0.45 is the value that we want to test

z would represent the statistic

p_v represent the p value

Creating the hypothesis

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Null hypothesis:p=0.45  

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The statistic is:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing we got:

z=\frac{0.40 -0.45}{\sqrt{\frac{0.45(1-0.45)}{370}}}=-1.933  

Calculating the p value  

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p_v =2*P(z  

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