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4 years ago

The study of Mixture

Chemistry

1 answer:

Nitella [24]4 years ago

5 0

Answer:

Mixtures can be either homogeneous or heterogeneous. A mixture in which its constituents are distributed uniformly is called homogeneous mixture, such as salt in water. A mixture in which its constituents are not distributed uniformly is called heterogeneous mixture, such as sand in water.

Explanation:

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If an equivalent (eq) is defined as a mole of charge, what is the concentration of ca2 in blood plasma in eq if its concentratio

diamong [38]

The concentration of ca 2 in blood plasma in equivalent if its concentration is 0.0080.

Concentration means the amount of or parts in terms of the alternative components. For acid–base reactions, the equivalent weight of an acid or base is the mass which materials or reacts with one mole of hydrogen

In chemistry, equal weight (additionally known as gram equal is the mass of 1 equivalent, that is the mass of a given substance as a way to integrate with or displace a fixed amount of any other substance. The equivalent weight of an detail is the mass which combines with or displaces 1.008 gram of hydrogen or eight. Zero grams of oxygen or 35.five grams of chlorine. those values correspond to the atomic weight divided through the usual valence for oxygen as example that is sixteen.

Charge on one Ca 2+ ion = + 2 .

Concentration of calcium ion = 0.0040M

⇒ Concentration of Ca 2 + in blood plasma = 0.0040 × 2

= 0.0080 equivalent Ca 2 answer

Learn more about concentration here :- brainly.com/question/14469428

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4 0

2 years ago

Changes in appearance...

Serjik [45]

I'm not quite sure but I think if you field the corner or cut it it would physically change it while not creating something new (chemical change).

3 0

4 years ago

An 8.89 g sample of an aqueous solution of nitric acid contains an unknown amount of the acid. If 27.1 mL of 0.581 M potassium h

worty [1.4K]

Answer:

The percent by mass of nitric acid in the mixture is 11.1 %

Explanation:

Step 1: Data given

Mass of HNO3 = 8.89 grams

Volume of KOH = 27.1 mL = 0. 0271 L

Molarity of KOH = 0.581 M

Step 2: The balanced equation

HNO 3 + KOH → KNO 3 + H 2 O

Step 3: Calculate the moles of KOH

Moles of KOH = molarity KOH * volume

Moles KOH = 0.581 M * 0.0271 L

Moles KOH = 0.0157 moles

Step 4: Calculate moles of HNO3

For 1 mol of KOH we need 1 mol of HNO3

For 0.0157 moles of KOH we need 0.0157 moles of HNO3

Step 5: Calculate mass of HNO3

Mass KOH = moles KOH * molar mass KOH

Mass KOH = 0.0157 moles * 63.01 g/mol

Mass KOH = 0.989 grams

Step 6: Calculate mass % HNO3 in sample

mass % = (0.989 grams / 8.89 grams)*100%

mass % = 11.1 %

The percent by mass of nitric acid in the mixture is 11.1 %

3 0

4 years ago

A 0.286-g sample of gas occupies 125 ml at 60. cm of hg and 25°

irga5000 [103]

Using the Equation: PV=nRT
Where P is the pressure 60 cmHg or 600 mmHg or 600/760= 0.789 atm
V is the volume 125 ml or 0.125 L, n is the number of moles, R is a constant 0.082057, and T is temperature 25 °C or 298 K;
Therefore:
0.789 × 0.125 = n × 0.082057 × 298
n = 0.0987/24.45
= 0.004036 mol
0.004036 mole has a mass of 0.286 g
Hence; 1 mole has a mass of 0.286/0.004036
= 70.8 g /mol
Therefore the molar mass of the gas is 71 g/mol (2 sfg)

4 0

3 years ago

A sample of gas has an initial volume of 22.6 L at a pressure of 1.67 atm. If the sample is compressed to a volume of 10.0 L : ,

Sphinxa [80]

Answer:

3.74 atmospheres

Explanation:

If the temperature is constant, then the formula is

V*P = V1 * P1

V = 22.6 L

P = 1.67 atm

V1 = 10.0 L

P1 = ??

=============

22.6 * 1.67 = 10 * P1

37.742 = 10 * P1

37.742/10 = P1

P1 = 3.742

Note there are 3 sig digs in each given, so the answer should be

P1 = 3.74 atmospheres

8 0

3 years ago