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jonny [76]
2 years ago
11

What is the pH of a 0.28 M solution of ascorbic acid

Chemistry
1 answer:
Nady [450]2 years ago
3 0

Hey there!

Values Ka1 and Ka2 :

Ka1 => 8.0*10⁻⁵

Ka2 => 1.6*10⁻¹²

H2A + H2O -------> H3O⁺  + HA⁻

 Ka2 is very less so I am not considering that dissociation.

Now Ka = 8.0*10⁻⁵ = [H3O⁺] [HA⁻] / [H2A]

lets concentration of H3O⁺  = X then above equation will be

8.0*10−5 = [x] [x] / [0.28 -x

8.0*10−5 = x² /  [0.28 -x ]

x² + 8.0*10⁻⁵x  - 2.24 * 10⁻⁵

solve the quardratic equation

X =0.004693 M

pH = -log[H⁺]

pH = - log [ 0.004693 ]

pH = 2.3285

Hope that helps!

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Answer: 5.125 neutrinos

Explanation:

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3 years ago
The standard free energy change for a reaction in an electrolytic cell is always:_________
sattari [20]

Answer: The standard free energy change for a reaction in an electrolytic cell is always positive.

Explanation:

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Relation of standard free energy change and emf of cell

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where,

\Delta G^o = standard free energy change

  n= no of electrons gained or lost

F= faraday's constant

E^0_{cell} = standard emf

E^0_{cell}   = standard emf = -ve  , for non spontaneous reaction

Thus  \Delta G^o=(-ve)(-ve)=+ve

Thus standard free energy change for a reaction in an electrolytic cell is always positive.

8 0
2 years ago
Calculate the pH of a solution that [H3O4] of 7.22x10-7M
schepotkina [342]
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5 0
2 years ago
Explain why vanadium (radius=134 pm) and copper (radius=128 pm) have nearly identical atomic radii, even though the atomic numbe
Viktor [21]
<span>There are few main factors affecting the atomic radii, the outermost electrons and the protons in the nucleus and also the shielding of the internal electrons. I would speculate that the difference in radii is given by the electron clouds since the electrons difference in these two elements is in the d orbital and both has at least 1 electron in the 4s (this 4s electron is the outermost electron in all the transition metals of this period). The atomic radio will be mostly dependent of these 4s electrons than in the d electrons. Besides that, you can see that increasing the atomic number will increase the number of protons in the nucleus decreasing the ratio of the atoms along a period. The Cu is an exception and will accommodate one of the 4s electrons in the p orbital.

</span><span>Regarding the density you can find the density of Cu = 8.96g/cm3 and vanadium = 6.0g/cm3. This also correlates with the idea that if these two atoms have similar volume and one has more mass (more protons;  density is the relationship between m/V), then a bigger mass for a similar volume will result in a bigger density.</span>
7 0
3 years ago
Copper has a density of 8.96 g/cm3. If a thin sheet of copper measures 5.5 cm by 5.5 cm and has a mass of 12.96 g, what is its t
balandron [24]

Thickness of cooper sheet is 0.048 cm (Approx.)

Given that;

Density of copper = 8.96 g/cm³

Measures of copper sheet = 5.5 cm × 5.5 cm

Mass of of copper sheet = 12.96 gram

Find:

Thickness of cooper sheet

Computation:

Volume = Mass / Density

Volume of cooper = 12.96 / 8.96

Volume of cooper = 1.4464

Volume of cooper = 1.45 cm³ (Approx.)

Volume of cooper sheet = 5.5 cm × 5.5 cm x Thickness

5.5 cm × 5.5 cm x Thickness = 1.45

Thickness of cooper sheet = 0.04793

Thickness of cooper sheet = 0.048 cm (Approx.)

Learn more:

brainly.com/question/24235924?referrer=searchResults

8 0
2 years ago
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